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    <p>I've been able to stream data to my third-party API using the following Scala controller code:</p> <pre><code>def uploadFile() = Action( parse.multipartFormData(myPartHandler) ) { request =&gt; Ok("Done") } def myPartHandler: BodyParsers.parse.Multipart.PartHandler[MultipartFormData.FilePart[Result]] = { parse.Multipart.handleFilePart { case parse.Multipart.FileInfo(partName, filename, contentType) =&gt; //Still dirty: the path of the file is in the partName... String path = partName; //Set up the PipedOutputStream here, give the input stream to a worker thread val pos:PipedOutputStream = new PipedOutputStream(); val pis:PipedInputStream = new PipedInputStream(pos); val worker:UploadFileWorker = new UploadFileWorker(path,pis); worker.contentType = contentType.get; worker.start(); //Read content to the POS Iteratee.fold[Array[Byte], PipedOutputStream](pos) { (os, data) =&gt; os.write(data) os }.mapDone { os =&gt; os.close() Ok("upload done") } } } </code></pre> <p>The UploadFileWorker is a really simple Java class that contains the call to the thrid-party API.</p> <pre><code>public class UploadFileWorker extends Thread { String path; PipedInputStream pis; public String contentType = ""; public UploadFileWorker(String path, PipedInputStream pis) { super(); this.path = path; this.pis = pis; } public void run() { try { myApi.store(pis, path, contentType); pis.close(); } catch (Exception ex) { ex.printStackTrace(); try {pis.close();} catch (Exception ex2) {} } } </code></pre> <p>}</p> <p>It's not completely perfect because I would have preferred to recover the path as a parameter to the Action but I haven't been able to do so. I thus have added a piece of javascript that updates the name of the input field (and thus the partName) and it does the trick.</p>
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