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2012-08-16T10:31:07.737
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<p>You could do it like this:</p> <pre><code>SDK_BYTE asByte(SdkVariant & var) { SDK_BYTE byte; bool const ok = var.toByte(byte); if (!ok) diePainfully(); return byte; } SDK_DOUBLE asDouble(SdkVariant & var) { SDK_DOUBLE d; bool const ok = var.toDouble(d); if (!ok) diePainfully(); return d; } SDK_BOOLEAN asBoolean(SdkVariant & var) { SDK_BOOLEAN b; bool const ok = var.toBool(b); if (!ok) diePainfully(); return b; } static const bool byteAndBooleanAreTheSame = std::is_same<SDK_BYTE, SDK_BOOLEAN>::value; template <bool b> struct VariantCastImpl { template <typename T> T cast(SdkVariant & var) const; template <> SDK_DOUBLE cast(SdkVariant & var) const { return asDouble(var); } template <> SDK_BYTE cast(SdkVariant & var) const { return asByte(var); } template <> SDK_BOOLEAN cast(SdkVariant & var) const { return asBoolean(var); } }; template <> struct VariantCastImpl<false> { template <typename T> T cast(SdkVariant & var) const; template <> SDK_DOUBLE cast(SdkVariant & var) const { return asDouble(var); } template <> SDK_BYTE cast(SdkVariant & var) const { if (var.type() == SdkVariant::SdkByte) { return asByte(var); } else if (var.type() == SdkVariant::SdkBoolean) { return asBoolean(var); } else { diePainfully(); return SDK_BYTE(); // dummy return, I assume diePainfully throws something } } }; template <typename T> T variant_cast(SdkVariant & var) { return VariantCastImpl<!byteAndBooleanAreTheSame>().cast<T>(var); }; </code></pre>
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1. POHow can I provide template specializations for typedefs of the same type?
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1. COWriting several specialized functions for the value retrieval is a valid approach, but eliminates the need for a template class. The first three functions (asByte, asDouble, asBoolean) would be enough.
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  USAlexander Tobias Bockstaller
2. COYou can use variant_cast<T> in generic code while you cannot do the same using the three asXXX-Functions. Other that that, I agree that just having the three functions will in general be enough to solve your problem. I have to admit that I considered your question a challenge, too ;)
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