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    <p>I do belive that <code>System.arraycopy</code> would actually just take all your data from one array, and put it into another one of the same length just shifted.</p> <p>Anyways thinking about that problem is a quite interesting task. The only Solution i could think about right now is to shit it one by one. Without using another Array it would look like that:</p> <pre><code>for(int i = 0; i &lt; shift;i++) { tmp = array[0]; for(int j = 0;j&lt;array.length-1;j++) array[j]=array[j+1]; array[array.length-1]=tmp; } </code></pre> <p>for Arrays greater than 30 items it is but more efficient to use this:</p> <pre><code>for (int i = 0; i &lt; shift; i++) { tmp = array[0]; System.arraycopy( array, 1, array, 0, array.length - 1 ); array[array.length - 1] = tmp; } </code></pre> <p>But for large arrays and great shift that are close to the array size aswell as for short arrays and small shifts this method wins the race:</p> <pre><code> int[] array2 = new int[shift]; for (int i = 0; i &lt; shift; i++) { array2[i] = array[i]; } System.arraycopy(array, shift, array, 0, array.length - shift); for (int i = array.length - shift; i &lt; array.length; i++) { array[i] = array2[shift + i - array.length]; } </code></pre> <p>Ive tested that with a few array sizes and shifts Here are the results for </p> <pre><code> int[] array = new int[100000]; int shift = 99999; </code></pre> <p>in nanoseconds: 1st method:5663109208 2nd method:4047735536 3rd method:6085690 So you should really use the 3rd method. Hope that helps</p>
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    1. POcircular left shift of an array by n positions in java
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    1. USWalter Lars Lee
    1. USWalter Lars Lee
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