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    <p>First of all, in Perl you are <em>not</em> required to define a subroutine before calling it; it would be a better practice to do so; hence the warning your code produces. However, there is nothing technically wrong in this regard; nor is this warning relevant to your problem.</p> <p>I believe the answer is indeed in your two declarations of the same variable with "my", coupled with the specific behavior of the Perl interpreter. Here is the explanation of this warning from <a href="http://www6.uniovi.es/perl/perldiag.html" rel="nofollow">perldiag</a>:</p> <blockquote> <p>``my'' variable %s masks earlier declaration in same scope (S) A lexical variable has been redeclared in the same scope, effectively eliminating all access to the previous instance. This is almost always a typographical error. Note that the earlier variable will still exist until the end of the scope or until all closure referents to it are destroyed.</p> </blockquote> <p>When your print statement happens, only the first declaration of $P has been processed by the interpreter, thus it prints 10, as you would expect. </p> <p>However, when you call the sub, Perl goes to look for the subroutine definition. It also has to find all of the other variable declarations preceding it, so that the sub can have access to lexical variables; it finds the second declaration, and thus your first $P is overwritten with a new $P. However, since this new $P hasn't been set to anything yet in your program, it is undefined.</p>
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