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POjqplot not evaluating string
 

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  1. POjqplot not evaluating string
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    <p>I am using jqplot and have constructed an array with the following PHP code</p> <pre><code>if($fiveRes){ $lastNum = mysql_num_rows($fiveRes); $testarray = array(); while($row = mysql_fetch_array($fiveRes, MYSQL_ASSOC)) { $testarray[] = array($row['GameDate'], floatval($row['WKP'])); } echo json_encode($testarray); } </code></pre> <p>This code outputs the correct code that I need to insert into the jqplot function. Here is the array generated by the code above:</p> <pre><code>[["2011-12-24",0],["2011-12-19",14],["2011-12-08",22],["2011-12-04",14],["2011-11-27",12]] </code></pre> <p>So currently i'm printing this array to the screen, and then using jQuery .text() to capture the string and place it inside a variable. I can echo out the var that I assigned the array string to and it works correctly, however when I pass it into the jqplot function it does nothing.</p> <pre><code>var p1array = $('.col.first .parray').text(); alert(p1array); //Alerts the correct array formatted like above. var plot1 = $.jqplot('jqplot0', [p1array], { title:'Last 5 Fantasy Points', axes:{ xaxis:{ renderer:$.jqplot.DateAxisRenderer, tickOptions:{ formatString:'%b&amp;nbsp;%#d' } }, yaxis:{ tickOptions:{ formatString:'' } } }, highlighter: { show: true, sizeAdjust: 7.5 }, cursor: { show: false } }); </code></pre> <p>To make it even more complicated, if I copy the string that the PHP generates and I hardcode it into a variable in JS it works. Any ideas why the jqplot plugin won't evaluate the string I get from using <code>$(this).text();</code>.</p> <p>Here is the jQplot example i'm modeling after: <a href="http://www.jqplot.com/tests/cursor-highlighter.php" rel="nofollow">http://www.jqplot.com/tests/cursor-highlighter.php</a></p>
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    1. USjsheffers
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    1. COI don't know why the text() is not working but Have you tried/or is there any problem using p1array = <?php echo $php_string_you_created;?>;
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      1. USTigerTiger
    2. COwhat happens if you use p1array without the brackets? ie var plot1 = $.jqplot('jqplot0', p1array, {...
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      1. USJim
    3. COTried without the brackets and I get the same result
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