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  1. PO
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    <p>I think you can solve your problem by adding a page number to your query. Unfortunately, this is moderately painful in mysql, because you have to use a self join or correlated subquery.</p> <p>Here is an example of how to do it with a correlated subquery:</p> <pre><code>select t.*, (select count(distinct order) from t t2 where t2.order &lt;= t.order) as pagenum from t order by pagenum </code></pre> <p>Based on your original query (but without putting it into a string):</p> <pre><code>with workouts as ( SELECT * FROM `movements` LEFT JOIN `classes` ON `movements`.`class_id` = `classes`.`class_id` LEFT JOIN `clients` ON `movements`.`class_id` = `clients`.`class_id` WHERE `classes`.`class_id` = '$class_id' AND `user_id` = ".$_session['user_id']." ) select wo.*, (select count(distinct order) from workouts wo2 where wo2.order &lt;= wo.order) as pagenum from workouts wo order by pagenum </code></pre> <p>This will almost work . . . just one caveat. You can put the "SELECT *" into the with clause because you have multiple columns with the same name. Put in the columns you need.</p> <p>I forget that mysql does not support the "with" statement. My apologies for the bad syntax. One work around is to use a view or temporary table. Otherwise, the query is a bit more complicated because the logic has to be repeated twice:</p> <pre><code>select wo.*, (select count(distinct order) from (SELECT * FROM `movements` LEFT JOIN `classes` ON `movements`.`class_id` = `classes`.`class_id` LEFT JOIN `clients` ON `movements`.`class_id` = `clients`.`class_id` WHERE `classes`.`class_id` = '$class_id' AND `user_id` = ".$_session['user_id']." ) wo2 where wo2.order &lt;= wo.order ) as pagenum from (SELECT * FROM `movements` LEFT JOIN `classes` ON `movements`.`class_id` = `classes`.`class_id` LEFT JOIN `clients` ON `movements`.`class_id` = `clients`.`class_id` WHERE `classes`.`class_id` = '$class_id' AND `user_id` = ".$_session['user_id']." ) wo order by pagenum </code></pre>
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    1. POdisplay partial results from a mysql query
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    1. USGordon Linoff
    1. USGordon Linoff
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    1. COI posted my query above along with a link to a screen shot of the query results as I can not figure out how your query would translate to my current query.
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    2. COMy understanding is that you want to break things apart by pages. So, this query adds a "pagenum" column into the return set. You can then choose whichever page of data you want. To make this work with your query, just put a "with t as (<your query>)" before this.
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    3. COSo what you have written above would follow my existing query I posted originally?
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