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POParsing a slash and apostrophe with Python regex
 

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  1. POParsing a slash and apostrophe with Python regex
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    <p>I am attempting to parse a Wikipedia SQL dump with the Python regular expressions library. The ultimate goal is to import this dump into PostgreSQL, but I know the apostrophes in strings need to be doubled, beforehand.</p> <p>Every apostrophe in a string in this dump is preceded by a backwards slash, though, and I'd rather not remove the backwards slashes.</p> <blockquote> <p>(42,'Thirty_Years\'_War',33,5,0,0)</p> </blockquote> <p>Using the command</p> <pre><code>re.match(".*?([\w]+?'[\w\s]+?).*?", line) </code></pre> <p>I cannot identify the apostrophe in the middle of 'Thirty_Years\'_War', when 'line' is parsed from a text file.</p> <p>For comparison, these lines work fine when parsed (sans the last line).</p> <blockquote> <p>The person's car</p> <p>The person's car's gasoline</p> <p>Hodges' Harbrace Handbook</p> <p>'Hodges' Harbrace Handbook'</p> <p>portspeople',1475,29,0,0),(42,'Thirty_Years\'_War',33,5,0,0)</p> </blockquote> <p>Correct and expected output (sans the last line):</p> <blockquote> <p>The person''s car</p> <p>The person''s car''s gasoline</p> <p>Hodges'' Harbrace Handbook</p> <p>('Hodges'' Harbrace Handbook')</p> <p>portspeople',1475,29,0,0),(42,'Thirty_Years\'_War',33,5,0,0)</p> </blockquote> <p>Using the command</p> <pre><code>re.match(".*?([\w\\]+?'[\w\s]+?).*?", line) </code></pre> <p>breaks it.</p> <blockquote> <p>The person''s car</p> <p>The person''''s car''''s gasoline</p> <p>Hodges'' Harbrace Handbook</p> <p>(''''''''Hodges'''''''' Harbrace Handbook'''''''')</p> <p>portspeople'''''''''''''''',1475,29,0,0),(42,''''''''''''''''Thirty_Years\''''''''''''''''_War'''''''''''''''',33,5,0,0)</p> </blockquote> <p>Is it stuck in some sort sort of loop? What is the correct regex code to use?</p> <p>I am not thinking about SQL injection attacks because this script is only going to be used for parsing dumps of Wikipedia articles (that don't contain examples of SQL injection attacks).</p>
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