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POspecific implementation of dictionary
 

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  1. POspecific implementation of dictionary
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    <p>I don't know if the title is apt, but for the time being this is my question:</p> <p>I have entries in text file(which has 2 columns) in the following format: </p> <pre><code>Name Time Santa 1.2 Jim 2.5 Santa 2.7 Santa 2.9 </code></pre> <p>I should form a dictionary which has Name as the key, (Time, Count) as the value. In the above names, Santa repeated 3 times and the time difference of consecutive occurances is less than 2 seconds. So the Count value associated with that entry is 3. If such case occurs, that entry should be deleted from dictionary. Otherwise, count value should be zero (If the 2 occurances of Santa happened 2 seconds apart and 3rd occurance happened after 2 seconds, then count is reinitialized to zero for that entry). </p> <p>Can this be implemented like this: Make the (Time, Count) as the list and make that list as the values to the keys? I am a newbie to Python, please excuse any mistakes.</p> <p>The pseudocode is something like this:</p> <pre><code>Read line in the file: if Santa is in dictionary: time_difference = time from column 2 of the line - dictionary[Santa] if(time_difference &lt; 2): Replace the old occurance with new one along with time # If the previous count value associated with Santa = 1, add 1 to make it 2 Make the Count associated with Santa = count+1 if(count associated with Santa = 3): delete the Santa entry else: Make count associated with Santa = 1 else: Add Santa to dictionary along with its time and make associated count = 1 </code></pre>
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    1. USJustin Carrey
    1. USJustin Carrey
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    1. COOh, that's a bit confusing. From what I gather, the `count` values for *all* entries remaining in the dictionary will be zero, so why store it in the first place? What `time` values are supposed to be in the final dictionary?
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      1. USSven Marnach
    2. CObecause if an entry occured 3 times with each less than 2 seconds apart, that entry is deleted. It is for that special purpose and Time is for comparing the previous occured instance of same entry. For example, if the count value of an entry is 2 and third occurance happened after 2 seconds of second occurance, then delete that entry
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      1. USJustin Carrey
    3. COTake a step back and write some clear requirements, perhaps with pseudo code even, and a sample case of what you want exactly. I'm very confused, and even though I may be able to decipher what you want after a while, it'd be easier for everyone if you could improve the question. Thanks :)
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      1. USDerek Litz
 

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