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    <p>Actually, on second reading, maybe this is the key:</p> <blockquote> <p>With methods which only take a single parameter, Scala allows the developer to replace the . with a space and omit the parentheses</p> </blockquote> <p>As mentioned on the blog post: <a href="http://www.codecommit.com/blog/scala/scala-for-java-refugees-part-6" rel="nofollow noreferrer">http://www.codecommit.com/blog/scala/scala-for-java-refugees-part-6</a> .</p> <p>So perhaps this is actually a very strict "syntax sugar" which <em>only</em> works where you are effectively <em>calling a method, on an object, which takes one parameter</em>. e.g.</p> <pre><code>1 + 2 1.+(2) </code></pre> <p>And nothing else.</p> <p>This would explain my examples in the question.</p> <p>But as I said, if someone could point out to be exactly where in the language spec this is specified, would be great appreciated.</p> <p>Ok, some nice fellow (paulp_ from #scala) has pointed out where in the language spec this information is:</p> <blockquote> <p>6.12.3: Precedence and associativity of operators determine the grouping of parts of an expression as follows.</p> <ul> <li>If there are several infix operations in an expression, then operators with higher precedence bind more closely than operators with lower precedence.</li> <li>If there are consecutive infix operations e0 op1 e1 op2 . . .opn en with operators op1, . . . , opn of the same precedence, then all these operators must have the same associativity. If all operators are left-associative, the sequence is interpreted as (. . . (e0 op1 e1) op2 . . .) opn en. Otherwise, if all operators are rightassociative, the sequence is interpreted as e0 op1 (e1 op2 (. . .opn en) . . .).</li> <li>Postfix operators always have lower precedence than infix operators. E.g. e1 op1 e2 op2 is always equivalent to (e1 op1 e2) op2.</li> </ul> <p>The right-hand operand of a left-associative operator may consist of several arguments enclosed in parentheses, e.g. e op (e1, . . . ,en). This expression is then interpreted as e.op(e1, . . . ,en).</p> <p>A left-associative binary operation e1 op e2 is interpreted as e1.op(e2). If op is rightassociative, the same operation is interpreted as { val x=e1; e2.op(x ) }, where x is a fresh name.</p> </blockquote> <p>Hmm - to me it doesn't mesh with what I'm seeing or I just don't understand it ;)</p>
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    1. POWhat are the precise rules for when you can omit parenthesis, dots, braces, = (functions), etc.?
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    1. COhmm, to further add to the confusion, this is also valid: (((((realService findAllPresentations) get) first) votes) size) must be equalTo 2, but not if i remove any of those parenthesis pairs...
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