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    <p>Your code is slightly wrong, since it counts sub-words as occurrences of words. For example "This is a bad test".count('a') will give 2 rather than 1.</p> <p>Word-splitting correctly is a bit tricky, but here's a simple start that breaks words at punctuation or spaces.</p> <pre><code>def input_files(f, word): print sum(re.split('[ .,;:"]').count(word) for line in f) </code></pre> <p>A good alternative would be to use a regular expression to find occurrences of the word (although I think this makes things slightly harder).</p> <p>This code has a few other improvements over your version: if you use a file object as an iterator, you get lines without having to do an explicit <code>readlines()</code> (this avoids reading the entire file into RAM and representing it as a list), and when you say <code>if word in line: s += line.count(word)</code> you're actually making things slower than if you just write <code>s += line.count(word)</code> since it requires 2 scans over the line rather than just one.</p> <p>I've also passed the word you're scanning for into the function, because it makes the code more obvious (and you could even write unit tests for this version).</p> <p>To continue... rather than printing the word-count out, you probably want to return it (since you want to find the files with the greatest word-count). Then you can count the occurrences of the given word per file, and sort them.</p> <p>Here's a solution, that uses command-line arguments and that doesn't have any error-checking. Usage: [program] word file1 file2...</p> <pre><code>import sys def words_in_file(filename, word): with open(filename, 'r') as f: return sum(re.split('[ .,;:"]', line).count(word) for line in f) def files_by_wordcount(filenames, word): counts = [(words_in_file(filename, word), filename) for filename in filenames] return sorted(counts, reverse=True) if __name__ == '__main__': for count, filename in files_by_wordcount(sys.argv[2:], sys.argv[1]): print filename, count </code></pre>
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    1. POcan't access different text files in python
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    1. USPaul Hankin
    1. USPaul Hankin
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      1. VTUpMod
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    1. CO+1 : I haven't noticed the code was counting the sub-words :-)
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      1. USm-r-r
    2. COthanks for your suggestion but i am new in python how i create the file object as the last answer also ask me to use file object as argument
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    3. COmy concentaration in only on UNI gram , till now i have no concern with bi gram
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