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POGiven an array, find zero values and replace them with the average of immediately bordering values
 

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  1. POGiven an array, find zero values and replace them with the average of immediately bordering values
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    <p>I have an array of temperature data by hour. Some hours have zero data instead of a temp. When graphing using Google Charts, the zero causes the line graph to plummet. My temporary fix was to replace the zero values with null, causing a break in the line graph. The ideal solution would be to take the values on either side of the zero, and average them. The array is in order by hour. Help?</p> <pre><code>$array = array( "1AM" =&gt; "65", "2AM" =&gt; "66", "3AM" =&gt; "68", "4AM" =&gt; "68", "5AM" =&gt; "68", "6AM" =&gt; "0", "7AM" =&gt; "70", "8AM" =&gt; "71", "9AM" =&gt; "71", "10AM" =&gt; "73", ); </code></pre> <p>Here's my script replacing the 0's with nulls:</p> <pre><code> $array = array (); foreach($parsed_json-&gt;history-&gt;observations as $key =&gt; $value) { $temp = (int)$value-&gt;tempi; if ($temp==0) { str_replace(0, null, $temp); } $hour = $value-&gt;date-&gt;hour; $array[$hour] = $temp; }; </code></pre> <p><a href="https://stackoverflow.com/questions/8816463/mysql-query-replace-null-value-in-a-row-with-average-values">This Example</a> would work great if the data was mine, but alas, it's from a JSON feed.</p> <p>Would I use an array_walk() sort of deal? How would I reference the current place in the array? Any help is appreciated!</p>
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