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    <p>I think what's he's trying to do is join the two datasets as if they were tables, joining by the brandName. From what I've been testing jQuery's $.extend() function does not take care of that, but merges objects according to their index in the Object arrays that it receives.</p> <p>I think the matching of the key would need to be done manually.</p> <pre><code>stock = [{"brandName":"Fender","gearShiftedPerMonth":"35","retailSalesPerMonth":"55"}, {"brandName":"Gibson","gearShiftedPerMonth":"23","retailSalesPerMonth":"43"}, {"brandName":"Epiphone","gearShiftedPerMonth":"10","retailSalesPerMonth":"13"}]; value = [{"brandName":"Gibson","stockValue":"1234"}, {"brandName":"Fender","stockValue":"975"}, {"brandName":"Epiphone","stockValue":"834"}]; var results = []; $(stock).each(function(){ datum1 = this; $(value).each(function() { datum2 = this; if(datum1.brandName == datum2.brandName) results.push($.extend({}, datum1, datum2)); }); }); </code></pre> <p>Which would result in:</p> <pre><code>[{"brandName":"Fender","gearShiftedPerMonth":"35","retailSalesPerMonth":"55","stockValue":"975"}, {"brandName":"Gibson","gearShiftedPerMonth":"23","retailSalesPerMonth":"43","stockValue":"1234"}, {"brandName":"Epiphone","gearShiftedPerMonth":"10","retailSalesPerMonth":"13","stockValue":"834"}] </code></pre> <p>Instead of what the use of <code>$.extend()</code> returns:</p> <pre><code>[{"brandName":"Gibson","gearShiftedPerMonth":"35","retailSalesPerMonth":"55","stockValue":"1234"}, {"brandName":"Fender","gearShiftedPerMonth":"23","retailSalesPerMonth":"43","stockValue":"975"}, {"brandName":"Epiphone","gearShiftedPerMonth":"10","retailSalesPerMonth":"13","stockValue":"834"}] </code></pre>
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    1. COThis is correct. However, see my answer below for a slightly different approach that would be more efficient for very large data sets at the expense of memory.
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