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    <blockquote> <p>nothing at all, because X(answer); could be interpreted as the declaration of a variable.</p> </blockquote> <p>Your answer is hidden in here. If you declare a variable, you invoke its default ctor (if non-POD and all that stuff).</p> <p>On your edit: To get a temporary, you have a few options:</p> <ul> <li><a href="http://liveworkspace.org/code/0d8f045cd715a27f126d26591098fc72"><code>(X(answer));</code></a></li> <li><a href="http://liveworkspace.org/code/87e18d40ffc27e49e0a07c9c05f1a775"><code>(X)answer;</code></a></li> <li><a href="http://liveworkspace.org/code/9619098847d97f1809fb02adb219ab5d"><code>static_cast&lt;X&gt;(answer)</code></a></li> <li><a href="http://liveworkspace.org/code/c78c002e32755e18b3c03eaac6951e85"><code>X{answer};</code></a> (C++11)</li> <li><a href="http://liveworkspace.org/code/d3393ff9bb3f302c3e9facfba22f1c64"><code>[]{ return X(answer); }();</code></a> (C++11, may incur copy)</li> <li><a href="http://liveworkspace.org/code/c803c5e68bf825d87e83cfa5294ee701"><code>void(), X(answer);</code></a></li> <li><a href="http://liveworkspace.org/code/ee2160ded0abd7dea87b2e743861af08"><code>X((void(),answer));</code></a></li> <li><a href="http://liveworkspace.org/code/d29e7f10fceadca7ec24fef163b8afb6"><code>true ? X(answer) : X();</code></a></li> <li><a href="http://liveworkspace.org/code/6eff0bb82d0c27334322ce22761e3ea2"><code>if(X(answer), false){}</code></a></li> <li><a href="http://liveworkspace.org/code/160fa87d472ebe74c3f5c2b44d7ff706"><code>for(;X(answer), false;);</code></a></li> <li><a href="http://liveworkspace.org/code/6914b3dbc2b6821e5bc51467dab97420"><code>X(+answer);</code></a></li> </ul>
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    1. POWhy does this call the default constructor?
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    1. COThank you, here is your bonus point: `.`
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    2. COThe `static_cast<X>(answer)` feels the "most C++" answer -- it's even recommended by an old [GCC documentation](http://gcc.gnu.org/onlinedocs/gcc-4.0.2/gcc/Volatiles.html) as a way to force an rvalue.
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    3. COWon't the brace initializer also maybe incur a copy?
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