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    <p><em><strong>UPDATE</strong> ok, Now I see you have edited and corected the mistake in your code in question. But still <code>&lt;?php =$hobby ?&gt;</code> doesn't make sense to me. It tells nothing to do to PHP parser. Use <code>echo</code> there, as explained in my answer.</em></p> <p>The only possible explanation of your problem is that the code being used in producing the <code>hobby</code> input field, specifically this fragment <code>value=&amp;lt;?=$hobby?&amp;gt;</code> is having problem.</p> <p>Reason:<br> PHP processes a <code>&amp;lt;?</code> and <code>&lt;?</code> differently. Former is echoed as-it-is, and latter tells PHP that PHP code is started at this point, and process it. Then an un-neccesarry <code>=</code> and missing <code>;</code>.</p> <p>Solution:<br> First of all use <code>value="&lt;?php echo $hobby; ?&gt;"</code> Use of full PHP tags () is always recommended over short tags () Then you need to tell PHP to echo/print the value of <code>$hobby</code> here by using <code>echo</code>. Now the output HTML should be <code>value="_Some_Hobby_"</code></p> <p>Now, if still the output HTML is <code>value=""</code> i.e. empty, then you need to check if <code>$hobby</code> actually holds a value.</p> <p>As seen at <a href="http://codepad.org/dvf9bwSd" rel="nofollow">http://codepad.org/dvf9bwSd</a> in Case 3,</p> <pre><code> value="&amp;lt;?php echo $hobby; ?&amp;gt;" </code></pre> <p>PHP Parser just chunks out the <code>&amp;lt;php .... ?&amp;gt;</code> thing as-it-is. So use literal <code>&lt;</code> &amp; <code>&gt;</code>.</p> <p>Now, in Case 1,</p> <pre><code>value="&lt;?php echo $hobby; ?&gt;" &lt;?php var_dump($hobby); ?&gt; </code></pre> <p>echoing <code>$hobby</code> variable <strong>without</strong> assigning it any value prints nothing. And <code>var_dump</code> also returns <code>NULL</code> </p> <p>Moving on to case-2, </p> <pre><code>&lt;?php $hobby = "Coding"; ?&gt; value="&lt;?php echo $hobby; ?&gt;" &lt;? var_dump($hobby); ?&gt; </code></pre> <p>defining/assigning a value to <code>$hobby</code> and then echoing it gives us the desired result <code>value="Coding"</code> and <code>var_dump</code> also says it is a <code>String</code> of <code>length=6</code></p>
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    1. COi did all these things dude...but don't know what's the fault in my code, i changed my code as u showed for the value, but still the value is empty, it is not showing any value there and my query shows the undefined value for the hobby field alone...
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    2. COOk, what is the output of `var_dump($user_data["hobby"]);`
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    3. COsee my question i've updated with the image how the error is showing in the hobby field when i echoed the query.
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