StackOverflow2013

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PO
primarykey
Id
11632523
data
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2012-07-24T13:59:29.540
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2012-07-24T13:59:29.540
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3
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text
Body
You need to copy the bit pattern verbatim without invoking any implicit conversions. The simplest way to do that is to take the address of the data and reinterpret it as a pointer to the intermediate "carrier" type before dereferencing it. Consider this: <pre><code>float source_float = 1234.5678f ; uint32_t transport_bits = *((uint32_t*)&source_float); float destination_float = *((float*)&transport_bits); </code></pre> The intermediate result in <code>transport_bits</code> is target dependent, in my test on x86, it is 0x449a522b, this being the bit representation of single precision float on that platform (floating point representation and endianness dependent). Either way the result in <code>destination_float</code> is identical to <code>source_float</code> having been transported via the <code>uint32_t</code> <code>transport_bits</code>. However this does require that the floating point representation of the originator is identical to that of the receiver which may not be a given. It is all a bit non-portable, The fact that your code does not work suggests perhaps that the representation does indeed differ between sender and receiver. Not only must the FP representation be identical but also the endianness. If they differ your code may have to do one or both of reorder the bits and calculate the floating point equivalent by extraction of exponent and mantissa. All so you nee to be sure that the transmission order of the bits is is the same order in which you are reassembling them. There are a number of opportunities to get this wrong.
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1. POConvert a 32 bits to float value
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1. USClifford
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1. POConvert a 32 bits to float value
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