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POIndexing a pandas dataframe by integer
 

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    <p>I can't seem to find an elegant way to <a href="http://pandas.pydata.org/pandas-docs/stable/indexing.html" rel="nofollow noreferrer">index</a> a <a href="http://pandas.pydata.org/pandas-docs/stable/dsintro.html" rel="nofollow noreferrer"><code>pandas.DataFrame</code></a> by an integer index. In the following example I want to get the value 'a' from the first element of the <code>'A'</code> column. </p> <pre><code>import pandas df = pandas.DataFrame( {'A':['a','b', 'c'], 'B':['f', 'g', 'h']}, index=[10,20,30] ) </code></pre> <p>I would expect <code>df['A'].ix[0]</code> and <code>df['A'][10]</code> both to return <code>'a'</code>. The <code>df['A'][10]</code> does return <code>'a'</code>, but <code>df['A'].ix[0]</code> throws a <code>KeyError: 0</code>. The only way I could think of to get the value <code>'a'</code> based on the index 0 is to use the following approach. </p> <pre><code>df['A'][df['A'].index[0]] </code></pre> <p>Is there a shorter way to get <code>'a'</code> out of the dataframe, using the 0 index?</p> <p><strong>Update</strong></p> <p>As of pandas 0.11 there is a another way to <a href="http://pandas.pydata.org/pandas-docs/stable/indexing.html#indexing-integer" rel="nofollow noreferrer">index by integer</a>.</p> <pre><code>df.iloc[0] # integer based, gives the first row df.loc[10] # label based, gives the row with label 10 </code></pre> <p>This <a href="http://pandas.pydata.org/pandas-docs/stable/indexing.html#deprecations" rel="nofollow noreferrer">supersedes</a> the <code>irow</code> approach . </p>
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