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    <p>Here are a few pointers. Note: For this exercise I will assume that when <code>N=0</code> that <code>Y % 400 == 0</code>.</p> <p><strong>1:</strong> There are a fixed number of days in each 400 year period <code>(400 * 365) + 100 + 1 - 4</code>.</p> <p>The <code>+100</code> is for the leap years, the <code>+1</code> is for the leap year every 400 years and the <code>-4</code> is for not having a leap year every 100 years.</p> <p>So your first line of code will be:</p> <pre><code>GetDate(int N, int &amp;Y, int &amp;M, int &amp;D) { const int DAYS_IN_400_YEARS = (400*365)+97; int year = (N / DAYS_IN_400_YEARS) * 400; N = N % DAYS_IN_400_YEARS; </code></pre> <p><strong>2:</strong> You can make your life a great deal easier if you treat March 1st as the first day of the year</p> <p><strong>3:</strong> Adding to the code in <strong>(1)</strong>, we can work out the year. Bear in mind that every fourth century begins with a leap year. So you can complete the calculation of the year with the following:</p> <pre><code> const int DAYS_IN_100_YEARS = (100*365) + 24; year += 100 * (N / DAYS_IN_100_YEARS) + (N &lt; DAYS_IN_100_YEARS ? 1 : 0); // Add an extra day for the first leap year that occurs every 400 years. N = N - (N &lt; DAYS_IN_100_YEARS ? 1 : 0); N = N % DAYS_IN_400_YEARS; </code></pre> <p><strong>4:</strong> Now you've sorted out the years, the rest is easy as pie (just remember <strong>(2)</strong>, and the process is easy).</p> <p>Alternatively you could use <a href="http://www.google.co.uk/url?sa=t&amp;rct=j&amp;q=&amp;esrc=s&amp;source=web&amp;cd=1&amp;ved=0CGQQFjAA&amp;url=http%3A%2F%2Fwww.boost.org%2Flibs%2Fdate_time%2F&amp;ei=oiINUNa5Eoqp0AWYzri8Cg&amp;usg=AFQjCNHqzBUilIMg5xFhJj_3uc-fjKAs-Q&amp;sig2=YJnZHL3NW8CwL3cmHq6QsA" rel="nofollow">boost::date</a>.</p>
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    1. COThere is something I don't understand... why `DAYS_IN_100_YEARS = (100*365) - 24`? Shouldn't it be `+24`? And when you add this to the year, you should multiply by `100`.
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    2. COJust fixed that
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    3. COBest answer because it actually helped me solve the problem, instead of adding another problem like other answers.
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