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POUsing twisted to process files
 

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    <p>I'm trying to set up a twisted xmlrpc server, which will accept files from a client, process them, and return a file and result dictionary back.</p> <p>I've used python before, but never the twisted libraries. For my purposes security is a non issue, and the ssh protocol seems like overkill. It also has problems on the windows server, since <code>termios</code> is not available. </p> <p>So all of my research points to xmlrpc being the best way to accomplish this. However, there are two methods of file transfer available. Using the <code>xml binary data</code> method, or the <code>http request</code> method.</p> <p>Files can be up to a few hundred megs either way, so which method should I use? Sample code is appreciated, since I could find no documentation for file transfers over xml with twisted.</p> <p><strong>Update:</strong></p> <p>So it seems that serializing the file with <code>xmlrpclib.Binary</code> does not work for large files, or I'm using it wrong. Test code below:</p> <pre><code>from twisted.web import xmlrpc, server class Example(xmlrpc.XMLRPC): """ An example object to be published. """ def xmlrpc_echo(self, x): """ Return all passed args. """ return x def xmlrpc_add(self, a, b): """ Return sum of arguments. """ return a + b def xmlrpc_fault(self): """ Raise a Fault indicating that the procedure should not be used. """ raise xmlrpc.Fault(123, "The fault procedure is faulty.") def xmlrpc_write(self, f, location): with open(location, 'wb') as fd: fd.write(f.data) if __name__ == '__main__': from twisted.internet import reactor r = Example(allowNone=True) reactor.listenTCP(7080, server.Site(r)) reactor.run() </code></pre> <p>And the client code:</p> <pre><code>import xmlrpclib s = xmlrpclib.Server('http://localhost:7080/') with open('test.pdf', 'rb') as fd: f = xmlrpclib.Binary(fd.read()) s.write(f, 'output.pdf') </code></pre> <p>I get <code>xmlrpclib.Fault: &lt;Fault 8002: "Can't deserialize input: "&gt;</code> when I test this. Is it because the file is a pdf?</p>
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