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POpointers and multi-dimensional arrays
 

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    <blockquote> <p><strong>Possible Duplicate:</strong><br> <a href="https://stackoverflow.com/questions/4810664/how-do-i-use-arrays-in-c">How do I use arrays in C++?</a><br> <a href="https://stackoverflow.com/questions/7586702/is-2d-array-a-double-pointer">Is 2d array a double pointer?</a><br> <a href="https://stackoverflow.com/questions/8669773/two-dimensional-arrays-and-pointers">Two dimensional arrays and pointers</a> </p> </blockquote> <p>I know that this is a very basic question but no amount of googling cleared this for me. That's why am posting it here. In c++ consider the declaration <code>int x[10];</code></p> <p>This is a 1-dimensional array with x being the base pointer that is it contains the address of the first element of the array. So <code>x</code> gives me that address and <code>*x</code> gives the first element.</p> <p>similarly for the declaration</p> <pre><code> int x[10][20]; </code></pre> <p>what kind of variable is <code>x</code> here. When i do </p> <pre><code> int **z = x; </code></pre> <p>the compiler says it cannot convert <code>int (*)[20]</code> to <code>int **</code>.And why does <code>cout&lt;&lt;x;</code> and <code>cout&lt;&lt;*x;</code> give the same value?? And also if i declare an array of pointers as </p> <pre><code> int *p[10]; </code></pre> <p>then is there a difference between <code>x</code> and <code>p</code> ( in their types) ?? because when one declares <code>int x[10]</code> and <code>int *p</code> then it is valid to assign <code>x</code> to <code>p</code> but it is not so in case of two dimensional arrays? why? Could someone please clear this for me or else provide a good resource material on this.</p>
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    1. COAll of this can be answered by reading the [C FAQ on *Arrays and Pointers*](http://c-faq.com/aryptr/index.html).
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    2. COyou can retrieve and element from the 2 dimensional array like this as well *(x + 20*(row) + col), so x is a multidimensional array still gives the pointer to the first value
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