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POExtracting parts of a webpage with python
 

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  1. POExtracting parts of a webpage with python
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    <p>So I have a data retrieval/entry project and I want to extract a certain part of a webpage and store it in a text file. I have a text file of urls and the program is supposed to extract the same part of the page for each url. </p> <p>Specifically, the program copies the legal statute following "Legal Authority:" on pages such as <a href="http://www.reginfo.gov/public/do/eAgendaViewRule?pubId=200904&amp;RIN=0648-AW10" rel="nofollow">this</a>. As you can see, there is only one statute listed. However, some of the urls also look like <a href="http://www.reginfo.gov/public/do/eAgendaViewRule?pubId=200210&amp;RIN=1205-AB16" rel="nofollow">this</a>, meaning that there are multiple separated statutes. </p> <p>My code works for pages of the first kind:</p> <pre><code>from sys import argv from urllib2 import urlopen script, urlfile, legalfile = argv input = open(urlfile, "r") output = open(legalfile, "w") def get_legal(page): # this is where Legal Authority: starts in the code start_link = page.find('Legal Authority:') start_legal = page.find('"&gt;', start_link+1) end_link = page.find('&lt;', start_legal+1) legal = page[start_legal+2: end_link] return legal for line in input: pg = urlopen(line).read() statute = get_legal(pg) output.write(get_legal(pg)) </code></pre> <p>Giving me the desired statute name in the "legalfile" output .txt. However, it cannot copy multiple statute names. I've tried something like this:</p> <pre><code>def get_legal(page): # this is where Legal Authority: starts in the code end_link = "" legal = "" start_link = page.find('Legal Authority:') while (end_link != '&lt;/a&gt;&amp;nbsp;'): start_legal = page.find('"&gt;', start_link+1) end_link = page.find('&lt;', start_legal+1) end2 = page.find('&lt;/a&gt;&amp;nbsp;', end_link+1) legal += page[start_legal+2: end_link] if break return legal </code></pre> <p>Since every list of statutes ends with <code>'&lt;/a&gt;&amp;nbsp;'</code> (inspect the source of either of the two links) I thought I could use that fact (having it as the end of the index) to loop through and collect all the statutes in one string. Any ideas?</p>
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    1. COThe page you are scraping offers these handy "Download RIN Data in XML" links. Whatever RIN is, there is some clean XML. Can't you use that instead? (`<LEGAL_AUTHORITY_LIST><LEGAL_AUTHORITY>blah1</LEGAL_AUTHORITY><LEGAL_AUTHORITY>blah2</LEGAL_AUTHORITY></LEGAL_AUTHORITY_LIST>`)
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    2. COWith python's ElementTree library, and @tiwo's suggestion, parsing the XMl should be dead simple
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    3. COJust noticed the XML link -- thanks. But it looks like I need to download each XML file, and I have hundreds of unique RINs to go through. Is there Python code for downloading the XMLs efficiently?
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