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POsimple java program not working -- while-loop
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2012-07-12T18:47:17.913
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2012-07-12T18:49:02.193
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<p>So I'm fairly new to programming, and I'm working on a simple practice program that finds a letters order in the alphabet. This should have been pretty easy...but for some reason I get a StringIndexOutOfBoundsException when I add a while loop. So the program does do what it should the first time...but will not allow me to test again with out re-running the program. I tested the while loop with nothing but a simple print statement inside and it worked, so I'm confused as to why the while loop isn't working with my alphabet program.</p> <p>Any help would be greatly appreciated thanks!</p> <pre><code>import java.io.*; public class test { public static void main(String[] args) throws IOException { BufferedReader in; in = new BufferedReader (new InputStreamReader (System.in)); boolean again=true; String response; while (again) { System.out.println("Enter a letter to find it's order in the alphabet"); char theLetter = (char) in.read(); System.out.println(theLetter + " is the " + convertLetter(theLetter) + "th letter of the alphabet"); System.out.println("want to play again?"); response = in.readLine(); if (response.charAt(0)=='n') { again=false; } } System.out.println("end program"); } public static int convertLetter(char TheLetter) { //number value 'a'=97 //number value 'b'=98 //number value 'c'=99 //subtracting 'a' from any other number will reveal how many places away that number is from the start //thus finding it's chronological place in the alphabet int NumberValue= (int)TheLetter; int a = 'a'; int CalulateOrder = (NumberValue - a) + 1; return CalulateOrder; } } </code></pre>
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<java><while-loop>
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simple java program not working -- while-loop
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