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11373151
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2012-07-07T07:28:22.360
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2012-07-07T07:28:22.360
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Okay, it is possible, and the way isn't too ugly. I have to add an additional level of inheritance: <pre><code> ITestA ITestB <-- These are the interfaces C has to fulfill, both with test() | | ITestA_X ITestB_X <-- These classes implement the interface by calling a | | function with a different name, like ITestA_test \__________/ which is in turn pure virtual again. | C <-- C implements the new interfaces </code></pre> Now C has no function <code>test()</code>, but when casting a <code>C*</code> to an <code>ITestA*</code>, the implementation of <code>test()</code> in <code>ITestA_test</code> will be used. When casting it to an <code>ITestB*</code>, even by a dynamic_cast from the <code>ITestA*</code>, the implementation of <code>ITestB_test</code> will be used. The following program prints: 3.14 0 <pre><code>#include <iostream> class ITestA { public: virtual ~ITestA() {}; virtual float test() =0; }; class ITestB { public: virtual ~ITestB() {}; virtual bool test() =0; }; class ITestA_X : public ITestA { protected: virtual float ITestA_test() =0; virtual float test() { return ITestA_test(); } }; class ITestB_X : public ITestB { protected: virtual bool ITestB_test() =0; virtual bool test() { return ITestB_test(); } }; class C : public ITestA_X, public ITestB_X { private: virtual float ITestA_test() { return 3.14; } virtual bool ITestB_test() { return false; } }; int main() { ITestA *a = new C(); std::cout << a->test() << std::endl; ITestB *b = dynamic_cast<ITestB *>(a); if (b) { std::cout << b->test() << std::endl; } delete(a); return 0; } </code></pre> Does this have any drawbacks you could think of?
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