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POJAVA - what is the difference between void and boolean methods?
 

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  1. POJAVA - what is the difference between void and boolean methods?
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    <p>I am completely new to JAVA. I am writing a wrapper-library in JAVA to make some functions available in Basic-like language.</p> <p>I got stock at a certain point when I noted that some code were not executed in the JAVA-library although the compiler did not complain (using Eclipse). I resolved it finally by replacing the code as follows:</p> <pre><code>public void VideoQuality(int vQuality) //did not work </code></pre> <p>into </p> <pre><code>public boolean VideoQuality(int vQuality) //works </code></pre> <p>Here are the complete code-snippets:</p> <pre><code> public void VideoQuality(int vQuality) //did not work {if (vQuality==16) { vidQuality=16; } else if (vQuality==-16) { vidQuality=-16; } else if (vQuality==0) { vidQuality=0; } else vidQuality=-16; vitamioExt.setVideoQuality(vidQuality); } public boolean VideoQuality(int vQuality) //works {if (vQuality==16) { vidQuality=16; } else if (vQuality==-16) { vidQuality=-16; } else if (vQuality==0) { vidQuality=0; } else vidQuality=-16; vitamioExt.setVideoQuality(vidQuality); return true; } </code></pre> <p>I think <strong>void</strong> corresponds to a sub in Visual Basic while <strong>boolean</strong> corresponds to a function.</p> <p>I found it odd however that the following code worked using <strong>void</strong></p> <pre><code>public void setVolume(float leftVolume,float rightVolume) { vitamioExt.setVolume(leftVolume, rightVolume); } </code></pre> <p>I am surely missing something very obvious but I can't see why the <strong>void</strong>-code would not work while the <strong>boolean</strong>-code worked.</p> <p>Maybe it depends how I call the code? </p> <p>Anyone who can shed some lights?</p> <p>EDIT: to clarify what was not working, I meant that the code:</p> <pre><code>vitamioExt.setVideoQuality(vidQuality); </code></pre> <p>did not execute in the void-snippet.</p> <p>EDIT2: vidQuality was declared in a different part of the code. I just posted the snippets since the problems were with those and variables were all functioning.</p> <p>EDIT3: At the end, I guess I must have called the void-snippet erroneously although the compiler did not compile. In either case, both snippets should execute although of course the void-snippet would be the right one to use since I did not expect a return-value. </p>
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    1. COI don't think it is possible to define two methods with the same signature and different return types in Java. The compiler should have failed in that line, provided that both methods are defined in the same class. This is not evident in your code.
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      1. USEdwin Dalorzo
    2. CO@moster67, it would be good for you to read an introductory Java book or tutorial first, perhaps the official Java Tutorial which should be available for download from Oracle. People can answer this question for you, but if you haven't learned basics like this, you will find it hard to make anything work in Java. It would be more efficient to just read the tutorial first before you start programming.
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    3. CO-1 because "did not work" is "not sufficient".
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