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    <p><strong>A complete, efficient and short transformation, using keys</strong>:</p> <pre><code>&lt;xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"&gt; &lt;xsl:output omit-xml-declaration="yes" indent="yes"/&gt; &lt;xsl:strip-space elements="*"/&gt; &lt;xsl:key name="kBibById" match="bib" use="@id"/&gt; &lt;xsl:template match="node()|@*" name="identity"&gt; &lt;xsl:copy&gt; &lt;xsl:apply-templates select="node()|@*"/&gt; &lt;/xsl:copy&gt; &lt;/xsl:template&gt; &lt;xsl:template match="link"&gt; &lt;xsl:call-template name="identity"/&gt; &lt;year&gt;&lt;xsl:value-of select="key('kBibById', @id)"/&gt;&lt;/year&gt; &lt;/xsl:template&gt; &lt;/xsl:stylesheet&gt; </code></pre> <p><strong>When this transformation is applied on the provided XML document:</strong></p> <pre><code>&lt;comp&gt; &lt;alink&gt; &lt;link id="0003"/&gt; &lt;link id="0001"/&gt; &lt;link id="0002"/&gt; &lt;/alink&gt; &lt;bibsection&gt; &lt;bib id="0001"&gt;2007&lt;/bib&gt; &lt;bib id="0002"&gt;2008&lt;/bib&gt; &lt;bib id="0003"&gt;2009&lt;/bib&gt; &lt;/bibsection&gt; &lt;/comp&gt; </code></pre> <p><strong>the wanted, correct result is produced:</strong></p> <pre><code>&lt;comp&gt; &lt;alink&gt; &lt;link id="0003"/&gt; &lt;year&gt;2009&lt;/year&gt; &lt;link id="0001"/&gt; &lt;year&gt;2007&lt;/year&gt; &lt;link id="0002"/&gt; &lt;year&gt;2008&lt;/year&gt; &lt;/alink&gt; &lt;bibsection&gt; &lt;bib id="0001"&gt;2007&lt;/bib&gt; &lt;bib id="0002"&gt;2008&lt;/bib&gt; &lt;bib id="0003"&gt;2009&lt;/bib&gt; &lt;/bibsection&gt; &lt;/comp&gt; </code></pre> <p><strong>Explanation</strong>:</p> <ol> <li><p>The <strong><a href="http://www.dpawson.co.uk/xsl/sect2/identity.html" rel="nofollow">identity rule</a></strong> copies every matched node "as-is".</p></li> <li><p>There is a single template overriding the identity template -- and it matches any <code>link</code> element. The code in the body of this template calls the identity template by name to process the matched <code>link</code> element, then constructs a <code>year</code> element, with a text node child whose value is the string value of the first <code>bib</code> element whose <code>id</code> attribute has the same value as the <code>id</code> attribute of the matched <code>link</code> element. Selecting this <code>bib</code> element is done using the <strong><a href="http://www.w3.org/TR/1999/REC-xslt-19991116#function-key" rel="nofollow"><code>key()</code></a></strong> function that references an <strong><a href="http://www.w3.org/TR/1999/REC-xslt-19991116#key" rel="nofollow"><code>xsl:key</code></a></strong> instruction named "kBibById".</p></li> </ol> <p><strong>Notice</strong>:</p> <p>The link to the identity rule above is temporarily inoperable -- for the time-being, please, use this one form the Internet Archives: </p> <p><a href="http://web.archive.org/web/20081229160200/http://www.dpawson.co.uk/xsl/sect2/identity.html" rel="nofollow">http://web.archive.org/web/20081229160200/http://www.dpawson.co.uk/xsl/sect2/identity.html</a></p>
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    1. COthanks What a simple and elegant solution. suppose in my input the bib value contains child node like this.. <bib><citation>(<year>something</year>)</citation></bib> how to get that value?
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    2. CO@user1501710: The string value of `<bib><citation>(<year>something</year>)</citation></bib>` is "(something)". So if you want to output "something" you only need to get rid of the brackets -- use: `<xsl:value-of select="translate(key('kBibById', @id), '()', '')"/>` . It would be good if you *accept* the answer (by clicking on the check-mark next to it) and ask a new question about any new problem you have -- the comments format is inconvenient for specifying code.
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    3. CO@DimitreNovatchev Link for `identity rule` appears to be broken.
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      1. USVaman Kulkarni
 

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