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POUITabbarController dismiss modal UINavigationController
 

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    <p>I got a very interesting problem here. My iPhone app has an UITabbarController as rootViewController in the AppDelegate.</p> <p>If the app is opened the first time, it must be configured basically. For this purpose I create an UINavigationController and tell the tabbarController to present it modally:</p> <pre><code>firstRun = [[firstRunViewController alloc] init]; navCtrl = [[UINavigationController alloc] initWithRootViewController:firstRun]; [[self tabBarController] presentModalViewController:navCtrl animated:NO]; </code></pre> <p>When the configuration is done, I'd like to get rid of the firstRunViewController. I'm using this technique very often, using <code>-dismissModalViewControllerAnimated:</code>.</p> <p>But in this constellation this doesn't work. It doesn't matter from what controller I'm calling the dismiss. I tried it via the tabbarController, the rootViewController, the currently active viewController, of cause self and several other controllers.</p> <p>EVERY TIME I call <code>-dismissModalViewControllerAnimated:</code> I get this exception:</p> <pre><code>'UIViewControllerHierarchyInconsistency', reason: 'presentedViewController for controller is itself on dismiss for: &lt;UINavigationController:… </code></pre> <p>Can anybody help? Thanks in advance, with kind regards, Julian</p> <p><strong>EDIT</strong> In my AppDelegate I'm using a UITabbarController as rootViewController for the main window:</p> <pre><code>self.window.rootViewController = self.tabBarController; [self.window makeKeyAndVisible]; </code></pre> <p>Then I'm creating an UINavigationController and tell the UITabbarController to present the modalViewController:</p> <pre><code>UINavigationController *navCtrl = [[UINavigationController alloc] initWithRootViewController:firstRun]; [[self tabBarController] presentModalViewController:navCtrl animated:NO]; </code></pre> <p>When I now call -dismissModalViewControllerAnimated: on the firstViewController I'm getting the error from above.</p>
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