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    <p>It <em>sounds</em> like you actually want to link instances of <code>Man</code> to an instance of <code>Person</code> that retains any properties added in its constructor, in which case you might really want something like this:</p> <pre><code>function Person(a, b) { this.a = a; this.b = b; } function Man() {} Man.prototype = new Person("val1", "val2"); var m = new Man(); console.log(m.a); </code></pre> <p>...which prints <code>val1</code>.</p> <h2>Additional Ramblings</h2> <p>The purpose of <code>inherit</code> is to create an object from a function whose <code>prototype</code> is that of the given super class (without explicitly using <code>new</code>), which is exactly what it does. Therefore, the following prints <code>string</code>:</p> <pre><code>function Person() {} Person.prototype.test = "string"; function Man() {} function inherit(superClass) { function F() {} F.prototype = superClass.prototype; return new F; } var t = inherit(Person); console.log(t.test); </code></pre> <p>But you generally want to assign the returned object to another function's prototype:</p> <pre><code>Man.prototype = inherit(Person); var m = new Man(); console.log(m.test); </code></pre> <p>...so that <code>m.test</code> also prints <code>string</code>, which means that objects created using <code>Man</code> are linked to <code>Person</code>'s <code>prototype</code>).</p> <p>Note that <code>Man.prototype.prototype</code> is <code>undefined</code> and -- this is the important part -- also meaningless. Functions have prototypes. Other objects (such as <code>Man.prototype</code>) do not. The <code>prototype</code> property is not magical in any other context. Assigning a value to a random object's <code>prototype</code> property doesn't do anything special. It's just another property.</p> <p>Note also that the thing we returned from <code>inherit</code> is linked to <code>Person</code> by way of its <code>prototype</code> and has no access to any properties added to <em>instances</em> of <code>Person</code>.</p>
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