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    <p>Assuming you are calling the search something like this:</p> <pre><code>for (var i = 0; i &lt; legs.length; i++) { service.search(legs[i], callback); } </code></pre> <p>then you can do this by keeping track of all the results, and the number of times you've been called back:</p> <pre><code>var callbacksOutstanding = legs.length; var allPlaces = []; var callback = function(legPlaces, status) { if (status == google.maps.places.PlacesServiceStatus.OK) { allPlaces.push.apply(allPlaces, legPlaces); } if (--callbacksOustanding === 0) { processPlaces(allPlaces); } }; for (var i = 0; i &lt; legs.length; i++) { service.search(legs[i], callback); } </code></pre> <p>Where <code>processPlaces</code> is some function you've written to process the complete array of <code>PlaceResult</code> objects.</p> <p>Now the three <code>var</code> statements there are <em>not</em> global variables if this is all wrapped in a function (as it should be), because in Javascript you can and should define functions inside other functions. And if you do so, the inner functions will have access to variables in the outer functions. So for me this might look like this:</p> <pre><code>function findAndProcessPlaces(legs) { var callbacksOutstanding = legs.length; var allPlaces = []; var callback = function(legPlaces, status) { if (status == google.maps.places.PlacesServiceStatus.OK) { allPlaces.push.apply(allPlaces, legPlaces); } if (--callbacksOustanding === 0) { processPlaces(allPlaces); } }; for (var i = 0; i &lt; legs.length; i++) { service.search(legs[i], callback); } } </code></pre> <p>NB: The <code>allPlaces.push.apply</code> line performs an in-place concatenation of one array to another. You could also write:</p> <pre><code>allPlaces = allPlaces.concat(legPlaces) </code></pre> <p>at this point.</p>
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    1. COThanks, this method worked and solved my problem. As callbacks are asynchronous and do not necessarily follow a sequential process, so one has to track the number of callbacks and wait till all callbacks are done. Your var callbacksOutstanding was a very good suggestion and I guess this was the key to solving this problem. Also the second most important thing is allPlaces.push(legPlaces) does not work. I dont know why, but you have to use allPlaces.push.apply(allPlaces, legPlaces); to append to the array which was also very critical in solving this problem. I didnt try concat approach.
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    2. COJust a quick note - In the final function which is created, the variable var allPlaces = []; should be outside the function findAndProcessPlaces as I want all the results from all legs have to be stored in allPlaces.
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