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Postsdbo
PO
 

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  1. PO
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    <p>you can do like this.. i have tried this and it works for me</p> <pre><code>private void uploadImage() { // TODO Auto-generated method stub try { String extStorageDirectory = Environment.getExternalStorageDirectory().toString()+"/SurveyFiles/"; pathToOurFile=extStorageDirectory+fileName+".jpg"; //Toast.makeText(this, pathToOurFile.toString(), 600).show(); //Toast.makeText(this, pathToOurFile, 600).show(); FileInputStream fileInputStream = new FileInputStream(new File(pathToOurFile) ); URL url = new URL(urlServer); connection = (HttpURLConnection) url.openConnection(); // Allow Inputs &amp; Outputs connection.setDoInput(true); connection.setDoOutput(true); connection.setUseCaches(false); // Enable POST method connection.setRequestMethod("POST"); connection.setRequestProperty("Connection", "Keep-Alive"); connection.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary); outputStream = new DataOutputStream( connection.getOutputStream() ); outputStream.writeBytes(twoHyphens + boundary + lineEnd); outputStream.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + pathToOurFile +"\"" + lineEnd); outputStream.writeBytes(lineEnd); bytesAvailable = fileInputStream.available(); bufferSize = Math.min(bytesAvailable, maxBufferSize); buffer = new byte[bufferSize]; // Read file bytesRead = fileInputStream.read(buffer, 0, bufferSize); while (bytesRead &gt; 0) { outputStream.write(buffer, 0, bufferSize); bytesAvailable = fileInputStream.available(); bufferSize = Math.min(bytesAvailable, maxBufferSize); bytesRead = fileInputStream.read(buffer, 0, bufferSize); } outputStream.writeBytes(lineEnd); outputStream.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd); // Responses from the server (code and message) connection.getResponseCode(); connection.getResponseMessage(); fileInputStream.close(); outputStream.flush(); outputStream.close(); } catch (Exception ex) { //Exception handling } </code></pre> <p>PathtoOurFile is the path of the image u want to upload and urlserver is the path of ur php file</p> <p>here is that php file</p> <pre><code>&lt;?php // Where the file is going to be placed $target_path = "path where u need to store on server"; / * Add the original filename to our target path. Result is "uploads/filename.extension" */ $target_path = $target_path . basename( $_FILES['uploadedfile']['name']); if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else{ echo "There was an error uploading the file, please try again!"; echo "filename: " . basename( $_FILES['uploadedfile']['name']); echo "target_path: " .$target_path; } ?&gt; </code></pre>
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    1. POHow to send Image with HttpPost in Android
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    1. USCool Compiler
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    1. COThanks for your kind and fast response. I am trying this meanwhile u let me know that my URL is okk?? I have asked after my Code. please check. thanks
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      1. USGeet taunk
    2. COur URL does not look ok to me. where exacly u want to save the image on server??
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    3. COI also feel the same. Server side expects some thing like this POST:Array ( [fname] => werewrwrr [submit] => Submit ) GET:Array ( ) FILE:Array ( [upload] => Array ( [name] => Water lilies.jpg [type] => image/jpeg [tmp_name] => /tmp/phptbDtnD [error] => 0 [size] => 83794 ) ) They are expecting File
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