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POCheck for presence of multiple words in list and return list of boolean
 

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    <p>I've defined a function that checks if one or more words are in a list, and it works fine, but now I'm trying to figure out how I should change my code so I get a <strong>list</strong> of boolean values depending on whether the word is in the list. These are the two separate functions I've been fiddling with:</p> <p><strong>This is the one without booleans, and it works perfectly to print the words and whether or not they appear in the text, but the function doesn't output a boolean value (it just prints, which is a bit messy I know)</strong></p> <pre><code>def isword(file): wordlist=input("Which word(s) would you like to check for in the text? ") wordlist=wordlist() file=chopup(file) ##This is another function of mine that splits a string(file) into a list for n in range(0,len(wordlist)): word=wordlist[n] n+=1 word=word.lower() ##so case doesn't matter when the person enters the word(s) if word in file: print(word, ":TRUE") for i in range(0,len(file)): if file[i]==word: print(i) else: print(word," :FALSE") </code></pre> <p><strong>This one outputs a boolean but for one word only. I'm wondering how to combine them so that I get a list of booleans as the output, no printing</strong></p> <pre><code>def isword(file): a=True wordlist=input("Which word(s) would you like to check for in the text? ") wordlist=wordlist() file=chopup(file) ##This is another function of mine that splits a string(file) into a list for n in range(0,len(wordlist)): word=wordlist[n] n+=1 word=word.lower() if word in file: a=a else: a=False return(a) </code></pre> <p><strong>I ended up with this, it works pretty well (my variable/function names are actually in French in the project cause this is for homework at a French uni)</strong></p> <pre><code>def presmot(fichier): result=[] listemots=input("Entrez le/les mots dont vous voulez vérifier la présence : ") listemots=listemots.split() fichier=decoupage(fichier) for n in range(0,len(listemots)): mot=listemots[n] mot=mot.lower() def testemot(mot): a=True if mot in fichier: a=a else: a=False return(a) result=[(mot,testemot(mot)) for mot in listemots] return(result) </code></pre> <p>The only annoying thing is that the Boolean comes up in English, oh well!</p>
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    1. USBill the Lizard
    1. USJesse James Walker
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    1. COEdited to improve code formatting :)
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      1. USRyan
    2. COOh, I just did it then! Yea it looked terrible, woops.
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      1. USJesse James Walker
    3. COlol no worries just tryin to help out :), you should put the language in there... looks like python
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      1. USRyan
 

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