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11031357
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0
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0
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1
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2012-06-14T10:38:50.450
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0
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2012-06-14T10:38:50.450
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0
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1455970
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10557692
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2
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0
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text
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<p>Here's a few approaches; all assume C++11. Tested on clang++ 3.2 with -std=c++11.</p> <pre><code>//Taking a function pointer argument (template types inferred) template <typename ret, typename ... Args> constexpr int arg_count(ret (*f)(Args...)) { return sizeof...(Args); } //Taking a function type (or related) directly template <typename T> struct ArgCount { static const int value = 0; }; template <typename Ret, typename ... Args> struct ArgCount<Ret(Args...)> { static const int value = sizeof...(Args); }; template <typename Ret, typename ... Args> struct ArgCount<Ret(*)(Args...)> { static const int value = sizeof...(Args); }; template <typename Ret, typename ... Args> struct ArgCount<Ret(&)(Args...)> { static const int value = sizeof...(Args); }; //Using the latter for dispatch template <int N> struct helper { template<typename F, typename T1, typename T2> static void call(F func, T1 t1, T2 t2); }; template <> struct helper<1> { template<typename F, typename T1, typename T2> static void call(F func, T1 t1, T2 t2) { func(t1); } }; template <> struct helper<2> { template<typename F, typename T1, typename T2> static void call(F func, T1 t1, T2 t2) { func(t1, t2); } }; template<typename F, typename T1, typename T2> void my_magic_method(F func, T1 t1, T2 t2) { helper<ArgCount<F>::value>::call(func, t1, t2); } //Testing #include <cstdio> void a(int a, int b) { printf("%i\n", a + b); } void b(int x) { printf("%i\n", x); } int main() { printf("%i %i\n", arg_count(a), arg_count(b)); printf("%i %i\n", ArgCount<decltype(a)>::value, ArgCount<decltype(b)>::value); my_magic_method(a, 1, 2); my_magic_method(b, 1, 2); } </code></pre>
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1. This table or related slice is empty.
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1. PODetermining number of arguments of C++ template functor
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1. PTAnswer
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1. USaddaon
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1. COI think you should explain more why doing this so OP understand fully your approaches.
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