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POSpring: how to parse uploaded zip file?
 

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  1. POSpring: how to parse uploaded zip file?
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    <p>I uploaded my <strong>zip</strong> archive to the server and want to open <code>.txt</code> and <code>.jpg</code> files in it. I successfully get my archive in my Controller and get the name of each file via <code>ZipEntry</code>. Now I want to open it but for this I should get a full path to my file. </p> <p>I haven't found how I can do that. Could you suggest some approach how to do that ? </p> <p><strong>Update</strong></p> <p>I try to use example have been suggested below but I am not be able open the file</p> <pre><code>ZipFile zFile = new ZipFile("trainingDefaultApp.zip"); </code></pre> <p>I have got the <code>FileNotFoundException</code></p> <p>So I return to my start point. I have upload form in Java Spring application. In controller I had got a zip archive as <code>byte[]</code></p> <pre><code>@RequestMapping(method = RequestMethod.POST) public String create(UploadItem uploadItem, BindingResult bindingResult){ try { byte[] zip = uploadItem.getFileData().getBytes(); saveFile(zip); </code></pre> <p>Then I had got each <code>ZipEntry</code></p> <pre><code> InputStream is = new ByteArrayInputStream(zip); ZipInputStream zis = new ZipInputStream(is); ZipEntry entry = null; while ((entry = zis.getNextEntry()) != null) { String entryName = entry.getName(); if (entryName.equals("readme.txt")) { ZipFile zip = new ZipFile(entry.getName()); // here I had got an exception </code></pre> <p>According to docs I did all right but as for me it is strange to pass the file name only and suspect that you successfully will open the file</p>
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    1. UStharindu_DG
    1. USWinte Winte
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    1. COWhat do you mean? You said you open it successfully; what do you not have a "full path" to?
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      1. POSpring: how to parse uploaded zip file?
      1. USDave Newton
    2. COI have opened CommonsMultipartFile that contains my zip archive as byte[]. I convert it to ZipInputStream and in loop have got a ZipEntry for each file in my archive. Now I want to read this .txt file and .jpg file but ZipEntry contains only names of this files. So I haven't a full path to this files and can't open it as new File("d:/some.txt")
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      1. POSpring: how to parse uploaded zip file?
      1. USWinte Winte
 

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