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    <p>A possible solution:</p> <pre><code>#include &lt;iostream&gt; #include &lt;type_traits&gt; class A { public: //... static const char fooString[]; }; const char A::fooString[] = "This is a Foo."; class B { public: //... static const char barString[]; }; const char B::barString[] = "This is a Bar."; class C { public: //... static const char fooString[]; }; const char C::fooString[] = "This is also a Foo."; void doFoo(const char*s) { std::cout &lt;&lt; "doFoo: " &lt;&lt; s &lt;&lt; "\n"; } void doBar(const char*s) { std::cout &lt;&lt; "doBar: " &lt;&lt; s &lt;&lt; "\n"; } template&lt;class T&gt; class Something { public: //This version should be called if T has a static member called "fooString", //so it should be called if T is either class A or C template &lt;typename TT = T, typename std::enable_if&lt;TT::fooString != 0, bool&gt;::type = false&gt; void doSomething() { doFoo(T::fooString); } //This version should be called if T has a static member called "barString", //so it should be called if T is class B template &lt;typename TT = T, typename std::enable_if&lt;TT::barString != 0, bool&gt;::type = false&gt; void doSomething() { doBar(T::barString); } }; int main() { Something&lt;A&gt; a; Something&lt;B&gt; b; Something&lt;C&gt; c; a.doSomething(); //should call doFoo(A::fooString) b.doSomething(); //should call doBar(B::barString) c.doSomething(); //should call doFoo(C::fooString) } </code></pre> <p>Output:</p> <pre><code>doFoo: This is a Foo. doBar: This is a Bar. doFoo: This is also a Foo. </code></pre>
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