StackOverflow2013

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10897165
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2012-06-05T12:17:47.143
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2012-06-05T12:30:57.387
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2012-06-05T12:30:57.387
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In short: The compiler doesn't need the dimension, because a array decays to a pointer. But any additional dimension is needed by the compiler, to calculate the correct location in memory. At first you need to know that an array in C/C++ is a linear continuous object in memory. Which is very efficient. Because an array in C/C++ is a linear continuous object in memory, an array will decay to a pointer. Copying the complete array will be a waste of time and memory and is not requiered. A pointer is anything needed to go through the array. To go through the array you can take the increment-operator or any calculation which evaluates to a valid address in the array. You can set a delimiter in the array itself i.e. '\0' in a String, or pass the length to the function seperatley to tell your code where the end of the array is. With multi-dimensional arrays the thing is a little bit more complicated. A multi-dimesional array is still only a linear continuous object in the memory! But the compiler needs the information about the additional dimensions to calculate to correct position in memory, imagine the following: <pre><code>char array[10][10]; // 0 - 99 </code></pre> correct: <pre><code>// formal argument tells your compiler, that each column is 10 elements long funca(int array[10][10]) { // access to element 25 (2 * 10 + 4, the 10 is known through your formal argument, remember that an array is null based) array[2][3] = 'x'; } </code></pre> wrong: <pre><code>// formal argument tells your compiler, that ech colum is 5 elements long funcb(int array[10][5]) { // access to element 15 (2 * 5 * + 4, the 5 is known through your formal argument, remember that an array is null based) array[2][3] = 'x'; } </code></pre> A note (or warning): Arrays in Java, especiallay (irregular) multi-dimensional arrays are completely different.
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1. POC++, multidimensional array
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1. PTAnswer
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1. USPeter
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1. USPeter
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