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POCombining MySQL queries
 

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    <p>I have two seperate tables in my DB, here the relevant fields:</p> <p>table images:</p> <pre><code>CREATE TABLE `images` ( `image_id` int(4) NOT NULL AUTO_INCREMENT, `project_id` int(4) NOT NULL, `user_id` int(4) NOT NULL, `image_name` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `image_description` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `date_created` date NOT NULL, `link_to_file` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `link_to_thumbnail` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `given_name` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `note` varchar(255) COLLATE utf8_unicode_ci NOT NULL, PRIMARY KEY (`image_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=51 ; </code></pre> <p>and table projects:</p> <pre><code>CREATE TABLE `projects` ( `project_id` int(4) NOT NULL AUTO_INCREMENT, `user_id` int(4) NOT NULL, `project_name` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `project_description` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `date_created` date NOT NULL, `date_last_edited` date NOT NULL, `shared` int(1) NOT NULL, `password` varchar(255) COLLATE utf8_unicode_ci NOT NULL, PRIMARY KEY (`project_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=25 ; </code></pre> <p>I would like to display in a variable $content, a gallery of the oldest image from each project as a link to that project page and I have no idea how the mysql query should be built. Can you please help me with this? I have tried several if and while statements but the results have been complete failures and i am at the end of my (very limited) knowledge. I'm about to jump out the window...</p> <p>So I would like to end up with</p> <pre><code>&lt;a href="index.php?page=projects&amp;id='.$projectid.'"&gt; &lt;img src="oldest_photo_of_project_x" /&gt; &lt;/a&gt; &lt;a href="index.php?page=projects&amp;id='.$projectid.'"&gt; &lt;img src="oldest_photo_of_project_y" /&gt; &lt;/a&gt; &lt;a href="index.php?page=projects&amp;id='.$projectid.'"&gt; &lt;img src="oldest_photo_of_project_z" /&gt; &lt;/a&gt; </code></pre> <p><strong>Update1:</strong></p> <p>To clarify I am trying to combine:</p> <pre><code>"SELECT * FROM projects WHERE user_id='$UserID' ORDER BY project_id DESC" </code></pre> <p>And maybe something like this:</p> <pre><code>$query = "SELECT images.project_id, projects.project_name ". "FROM images, projects ". "WHERE images.project_id = projects.project_id"; </code></pre>
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    1. COWhat do you mean "display in a variable"?
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    2. CO@eggyal: I mean echo the results into a variable so i can later in the html do `<?php echo $content; ?>`
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    3. COOkay, then that variable will need to hold considerably more than just database results - it will need to hold structured markup. This is unusual practice and I suspect perhaps not what you want to do. Better to output directly as one loops over a database recordset.
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