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  1. POx86 assembly - masm32: Issues with waiting for response
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    <p>I have created this program that takes two inputs and prints them out (simple, yes, but it's for practise). It compiles, and runs fine, but it doesn't do what I intended. Here is my code:</p> <pre><code>.386 .model flat, stdcall option casemap :none include \masm32\include\windows.inc include \masm32\include\kernel32.inc include \masm32\include\masm32.inc includelib \masm32\lib\kernel32.lib includelib \masm32\lib\masm32.lib .data num1 db "Enter a number:", 0 num2 db "Enter another number:", 0 .data? buffer1 dd 100 dup(?) buffer2 dd 100 dup(?) .code start: lea eax, num1 push eax call StdOut lea ebx, buffer1 push ebx call StdIn hlt lea eax, num2 push eax call StdOut lea edx, buffer2 push edx call StdIn xor eax, eax xor ebx, ebx xor edx, edx lea eax, buffer1 push eax call StdOut lea ebx, buffer2 push ebx call StdOut push 0 call ExitProcess end start </code></pre> <p>It displays this output:</p> <pre><code>Enter a number: Enter another number: </code></pre> <p>It should do:</p> <pre><code>Enter a number: ; wait for input. Enter another number: ; wait for input. ; continue with program. </code></pre> <p>Why does it print on one line? I tried putting <code>halt</code> in there to stop the process, but Windows stops the program from running, and says <code>the program is not responding</code>. </p> <p>EDIT:</p> <p>Here is the code that I said I would edit in:</p> <pre><code>xor eax, eax xor ebx, ebx xor edx, edx lea eax, buffer1 push eax call StdOut lea ebx, buffer2 push ebx call StdOut </code></pre> <p>When I run this with the previous code, it says <code>"This program is not responding."</code> Why is this?</p> <p>Any help would be appreciated.</p> <p>Regards,</p> <p>Progrmr</p>
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