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    <p>If you want just the word "yes" or "no" (i.e. "bayes theorem porno" and the "yesterday" ones <em>don't</em> match) then you can use <code>\b</code> as a boundary character in a regex: <a href="http://docs.oracle.com/javase/1.4.2/docs/api/java/util/regex/Pattern.html" rel="nofollow"><code>Pattern</code> JavaDoc</a>, <a href="http://docs.oracle.com/javase/tutorial/essential/regex/bounds.html" rel="nofollow">Boundaries tutorial</a></p> <p>Assuming you're already lower-casing the input then this should work:</p> <pre><code>Pattern yes = Pattern.compile(".*\\byes\\b.*"); Pattern no = Pattern.compile(".*\\bno\\b.*"); ... bool matchesYes = yes.matcher(input).matches(); bool matchesNo = no.matcher(input).matches(); if (matchesYes == matchesNo) { ... //Do "invalid answer" here - //we either matched both (true, true) or neither (false, false) } else if (matchesYes) { ... //Do "Yes" here } else { //Else matches No ... //Do "No" here } </code></pre> <p>Test code:</p> <pre><code>private static Pattern yes = Pattern.compile(".*\\byes\\b.*"); private static Pattern no = Pattern.compile(".*\\bno\\b.*"); /** * @param args */ public static void main(String[] args) { TestMethod("yes"); //Yes TestMethod("no"); //No TestMethod("yesterday"); //Bad TestMethod("fred-no-bob"); //No TestMethod("fred'no'bob"); //No TestMethod("fred no bob"); //No TestMethod("snow"); //Bad TestMethod("I said yes"); //Yes TestMethod("yes no"); //Bad TestMethod("no yes"); //Bad } private static void TestMethod(String input) { System.out.print("Testing '" + input + "': "); bool matchesYes = yes.matcher(input).matches(); bool matchesNo = no.matcher(input).matches(); if (matchesYes == matchesNo) { System.out.println("Bad"); } else if (matchesYes) { System.out.println("Yes"); } else { System.out.println("No"); } } </code></pre>
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    1. COThanks for the link, but I can't envisage how it would be used to omit surrounding letters OR white-space. Could you possibly elaborate please? EDIT - Just seen your update, checking now - Thank you
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    2. CO`\b` means "word boundary" and basically matches the point where the next character is anything that isn't a word character (`\w`) including the beginning and end of the line, so "no", "fred no bob" and "fred-no-bob" should match, but not "fred non bob". Try it somewhere like http://www.regextester.com/ (but without the escaped slashes - so just `\bno\b` on a lot of regex testing sites)
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    3. COThank you for the explanation and the regextester - I've been looking for something like that! I'm about to test in my application and will come back and mark the answer as the correct after I've put it through its paces! Thanks again.
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