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    <p>If I understand you well, then you use the <code>range(0, 10000)</code> only to simulate the sequence. Whenever you use the <code>yield</code> in a function definition, it becomes a <em>generator function</em>. When generator function is used (called), it returns iterator -- you do not see it. Try the following <code>gen()</code> instead:</p> <pre><code>def gen(n): while n &gt; 0: yield n n -= 1 # decrement the value </code></pre> <p>Then you typically use it in a loop:</p> <pre><code>for x in gen(10000): print x, # comma to suppress new line </code></pre> <p>If you have a function that returns your strings, just <code>yield s</code> instead of building the list. Then call the generator function and collect only the values that you want (here not strings but numbers divisible by 100):</p> <pre><code>lst = [] # init for x in gen(10000): if x % 100 == 0: lst.append(x) print lst </code></pre> <p>The loop can be also replaced by so called list comprehension:</p> <pre><code>lst = [ x for x in gen(10000) if x % 100 == 0 ] print lst </code></pre> <p>...which is more understandable (i.e. resembles the above loop) when you write the same like that:</p> <pre><code>lst = [ x for x in gen(10000) if x % 100 == 0 ] print lst </code></pre> <p>But you can use a generator function wherever a sequence is expected. If your generator can implement the decision whether your element is to be collected, then you can simply make a list of the produced elements like this:</p> <pre><code>lst = list(gen(100)) print lst </code></pre>
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    1. POExplaining python generator for a long list
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    1. CO+1 for a good explanation
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      1. USNiklas B.
 

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