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    <p>When you pass variables in JavaScript you're passing a copy of a reference to a value if it's an object, but if it's a primitive (like a true/false) you're copying the actual value. This basically means, if you pass in an object and modify one of the object's properties, you'll be modifying the original object. But if you pass in a primitive like true/false, you'll just be modifying the copy, and not the original value. So if your goal is to modify the original values, one option is to store those values in an object and pass in the object instead. For example:</p> <pre><code>var object = { pants: true, house: true, hair: {} }; function modifyObject(obj) { obj.pants = true; obj.house = true; obj.hair = true; } </code></pre> <p>If you want to modify an arbitrary number of arguments, just remember that if you're passing in true/false you're copying those values. So if you change them inside the function you won't be modifying the original values.</p> <p>A quick way to remember this is if you ever pass an object or an array, you're modifying the actual object. Anything else, you're modifying a copy.</p> <p>Edit</p> <p>So interpreting what you want to do literally, you could write this:</p> <pre><code>var a = true, b = true; /* pass in variable names */ function makeFalse() { var i, len; for (i = 0, len = arguments.length; i &lt; len; ++i) { window[arguments[i]] = false; } } makeFalse("a", "b"); </code></pre> <p>But I can't think of a good reason to do this :-). I would use configuration objects to store flags and state variables, not global variables.</p>
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    1. POJavascript function that takes variable number of arguments - changes their value - and then returns them
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    1. COgood explanation, with the one exception that modifying the object variable itself wont do anything, but modifying its properties will.
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    2. COThanks for the clarification! I found a good way to think about it is that variable labels or names are separate from the values that they point to. The variable names are always separate in the function. If you reassign the variable inside the function you're just reassigning that local variable.
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    3. COthats a great explanation. Just makes me cringe thinking of pointers....
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