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    <p>Two words - <strong>integer overflow</strong></p> <p>While not an expert in python, I assume it may expand the size of the integer type according to its needs.</p> <p>In Java, however, the size of an <code>int</code> type is fixed - 32bit, and since <code>int</code> is signed, we actually have only 31 bits to represent positive numbers. Once the number you assign is bigger than the maximum, it overflows the int (which is - there is no place to represent the whole number). </p> <p>While in the C language the behavior in such case is undefined, in Java it is well defined, and it just takes the least 4 bytes of the result.</p> <p>For example:</p> <pre><code>System.out.println(Integer.MAX_VALUE + 1); // Integer.MAX_VALUE = 0x7fffffff </code></pre> <p>results in:</p> <pre><code>-2147483648 // 0x7fffffff + 1 = 0x800000000 </code></pre> <p><strong>Edit</strong></p> <p>Just to make it clearer, here is another example. The following code:</p> <pre><code>int a = 0x12345678; int b = 0x12345678; System.out.println("a*b as int multiplication (overflown) [DECIMAL]: " + (a*b)); System.out.println("a*b as int multiplication (overflown) [HEX]: 0x" + Integer.toHexString(a*b)); System.out.println("a*b as long multiplication (overflown) [DECIMAL]: " + ((long)a*b)); System.out.println("a*b as long multiplication (overflown) [HEX]: 0x" + Long.toHexString((long)a*b)); </code></pre> <p>outputs:</p> <pre><code>a*b as int multiplication (overflown) [DECIMAL]: 502585408 a*b as int multiplication (overflown) [HEX]: 0x1df4d840 a*b as long multiplication (overflown) [DECIMAL]: 93281312872650816 a*b as long multiplication (overflown) [HEX]: 0x14b66dc1df4d840 </code></pre> <p>And you can see that the second output is the least 4 bytes of the 4 output</p>
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    1. POWhy do these two similar pieces of code produce different results?
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    1. POWhy do these two similar pieces of code produce different results?
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    1. COInteresting. Can you provide context?
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    2. COSeriously, OP states s/he is a beginner - give a little more detail here.
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    3. CO@Zolani13 - please see edit.
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