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    <p>Below is the exact solution (assuming that your php and mysql resides on the same server)</p> <p>suppose your csv file is</p> <pre><code>"1";"Desserts";"1";"category/vcm_s_kf_repr_806x645_7.jpg" "2";"Beverages";"1";"category/aagya.jpg" "3";"apetizers";"1";"category/Koala.jpg" "13";"Breakfasts";"1";"category/Lighthouse_2.jpg" "5";"Vegeterian entries";"1";"category/Desert.jpg" "6";"Naan and Breads";"1";"category/Lighthouse_1.jpg" "7";"Mexican";"1";"category/vcm_s_kf_repr_832x624_2.jpg" </code></pre> <p>say you have files like 001.csv, 002.csv and so on make one table exactly with same field that are in csv files</p> <pre><code>CREATE TABLE `sample` ( `id` INT NOT NULL AUTO_INCREMENT , `name` VARCHAR( 100 ) NOT NULL , `flag` INT NOT NULL , `path` VARCHAR( 100 ) NOT NULL , PRIMARY KEY ( `id` ) , UNIQUE ( `id` ) </code></pre> <p>Then run a code below according to your customization </p> <pre><code>mysql_connect("localhost","root",""); mysql_select_db("csv"); //find the current working f=directory $dir=getcwd(); foreach (glob("*.csv") as $key=&gt;$val) { echo $sql="LOAD DATA INFILE '".$dir."//".$val."' INTO TABLE sample"; //now fire your update query , as an example here i am trying to replace all jpg with gif mysql_query($sql) or die(mysql_error()); echo $update="UPDATE sample SET path=REPLACE( path, '.jpg', ',bmp' )"; mysql_query($update); //delete the table for next csv echo $outfile="SELECT * INTO OUTFILE '" .$dir."/converted_".$val."' FIELDS TERMINATED BY ',' OPTIONALLY ENCLOSED BY '\"' LINES TERMINATED BY '\n' FROM sample"; mysql_query($outfile); $del="delete from smaple"; mysql_query($del); } </code></pre>
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    1. POUpdate the record in all csv file by php
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    1. COif you put all the csv files in a table, then export those csv file, there will be only one csv file. i want to get import 50 csv files. export 50 csv files.
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    2. COgo through the code carefully, i have created new csv file inside each loop
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