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2012-05-06T21:16:00.070
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2012-05-06T22:18:31.820
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I understand you want to tile only a subset of the texture, right? Then things get complicated. Assume we want to tile u-coord between u1 and u2 values, u1 < u2. Then we need a function f(u), so that <pre><code>f(0.0) = u1 f(0.5) = (u1+u2)/2 f(0.9999) = u2 f(1.0) = u1 f(1.5) = (u1+u2)/2 f(1.9999) = u2 f(2.0) = u1 and so on... </code></pre> An appropriate function is <code>f(u) = frac(u) * (u2-u1) + u1</code> The same goes for v-coord, <code>f(v) = frac(v) * (v2-v1) + v1</code> Notice that it's tiling without mirroring. If you need mirroring, then the function should be a triangular-wave function, which is <code>t(x) = arcsin(sin(pi*(x-0.5)))/pi+0.5</code> and <code>f(u) = t(u) * (u2-u1) + u1</code>. Using trigonometric functions can be expensive though. I don't know if it's possible with fixed pipeline, but you can do it easily in pixel shader (HLSL code): <pre><code>// float2 tex_coord -> (u,v) from vertex shader, in [0,n] range, // n - number of repetitions // float2 tex1, tex2 -> constants, subrange of [0,1] coords that will be tiled // no mirroring float4 color = tex2D(sampler, frac(tex_coord) * (tex2-tex1) + tex1); </code></pre> or <pre><code>// mirroring, t(x) = arcsin(sin(pi*(x-0.5)))/pi+0.5 float4 color = tex2D(sampler, t(tex_coord) * (tex2-tex1) + tex1); </code></pre> EDIT: a better way to compute triangular-wave function: <code>t1(x) = abs(2(0.5x-floor(0.5x+0.5)))</code> or <code>t2(x) = abs(2(frac(0.5x+0.5))-1)</code> (not exactly the same as t1 but correct for non-negative numbers).
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1. POHow would I tile a section of a texture in screen space?
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1. COEverything I've looked into shows it's really impossible to do it in the fixed function pipeline, sadly, but it's nice to see you going above and beyond for the pixel shader code. Thanks for the response :D
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