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    <p>You would not have asked that question if you had asked the compiler to help you (No offense!). The compiler is your friend. Enable it's warnings. For example GCC with</p> <pre><code>gcc -Wall yourcode.c </code></pre> <p>gives you</p> <pre><code>yourcode.c: In function ‘fill’: yourcode.c: 11:5: warning: implicit declaration of function ‘send’ yourcode.c: At top level: yourcode.c:15:5: warning: return type defaults to ‘int’ yourcode.c:22:5: warning: return type defaults to ‘int’ yourcode.c: In function ‘send’: yourcode.c:26:5: warning: control reaches end of non-void function yourcode.c: In function ‘main’: yourcode.c:19:5: warning: control reaches end of non-void function </code></pre> <p>Now you know that you should have written a prototype for function <code>send</code> or moved it's definition above the first usage. And as the compiler assumes a default return type for <code>send</code> you obviously forgot to specify it (here apparently <code>void</code> as you don't have any return value). For <code>main</code> the return type <code>int</code> and an </p> <pre><code>return 0; </code></pre> <p>is missing.</p> <p>With the said modifications the compiler will tell you</p> <pre><code>yourcode.c: In function ‘fill’: yourcode.c:12:5: error: incompatible type for argument 1 of ‘send’ yourcode.c.c:7:6: note: expected ‘struct xxx *’ but argument is of type ‘struct xxx’ </code></pre> <p>and you will notice you have one redundant * in</p> <pre><code>send(*create); </code></pre> <p>which dereferences your pointer. Note: You do NOT want to dereference your pointer, because you have to forward <em>the pointer</em> to <code>send</code> and not the value. Change the line to</p> <pre><code>send(create); </code></pre> <p>et Voilà.</p>
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