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    <p>In Ext.window.Window, there's a property called '<em>modal</em>': set it to true.</p> <p>Otherwise, use the <strong>WindowManager</strong> to manage your windows: in this case you have to follow the following steps:</p> <ol> <li><strong>register</strong> your windows to the WindowManager (<em>Ext.WindowManager.register (winId)</em>)</li> <li>use <strong>bringToFront</strong> method to set your window on top (<em>Ext.WindowManager.bringToFront (winId)</em>)</li> <li>finally, check the element on top with the <strong>getActive</strong> method (<em>Ext.WindowManager.getActive ()</em>)</li> </ol> <p>E.g.:</p> <pre><code>Ext.create ('Ext.window.Window', { title: 'Your window' , width: 300 , height: 300 , html: 'ciao ciao' , modal: true }).show (); </code></pre> <p>Or:</p> <pre><code>var win1 = Ext.create ('Ext.window.Window', { title: 'Your window' , id: 'firstWin' , width: 300 , height: 300 , html: 'ciao ciao' , }); win1.showAt (50, 50); var win2 = Ext.create ('Ext.window.Window', { title: 'Your window' , id: 'secondWin' , width: 300 , height: 300 , html: 'I love pizza' , }); win2.showAt (60, 60); // Register your floating objects (window in this case) to the WindowManager Ext.WindowManager.register (win1); Ext.WindowManager.register (win2); // Bring 'firstWin' on top Ext.WindowManager.bringToFront ('firstWin'); // Then, check the zIndexStack alert (Ext.WindowManager.getActive().getId ()); // this is firstWin, the window with the highest zIndex </code></pre> <p>Hope this help you.</p> <p>Cyaz</p>
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    1. COThat's nice, and the **main question** is: **HOW** to detect that new window is showed over the my window?
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    2. COAh, now I got it ;) Well, first you have to register your windows to the WindowManager. Then, check the zIndexStack of the WindowManager ;) The first element of the stack is that with the highest zIndex. Ext.WindowManager.zIndexStack[0] is your solution but I think the same thing should be done by Ext.WindowManager.getActive() but in my experiments it doesn't work... Now look to my first answer with the entire solution: it's just edited ;)
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    3. COOk, I just understood how to get the window with the highest zIndex through Ext.WindowManager.getActive(): instead of using toFront() method of each windows, you have to use Ext.WindowManager.bringToFront(id/object) and then check it with Ext.WindowManager.getActive() ;) Look to the edited solution. Ciao!
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