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POHow do I assign the result of a function object to a local in a boost::spirit semantic action
 

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  1. POHow do I assign the result of a function object to a local in a boost::spirit semantic action
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    <p>Im not really sure why the following code gives me the following error in GCC 4.6.3 </p> <p>no match for ‘operator=’ in ‘boost::spirit::_a = boost::phoenix::function::operator()(const A0&amp;) const [with A0 = boost::phoenix::actor >, F = make_line_impl, typename boost::phoenix::as_composite, F, A0>::type = boost::phoenix::composite, boost::fusion::vector, boost::spirit::argument&lt;0>, boost::fusion::void_, boost::fusion::void_, boost::fusion::void_, boost::fusion::void_, boost::fusion::void_, boost::fusion::void_, boost::fusion::void_, boost::fusion::void_> >]((* &amp; boost::spirit::_1))’</p> <p>Is it even possible to assign the result of a lazy function object to a qi placeholder? </p> <pre><code>#include &lt;string&gt; #include &lt;boost/spirit/include/phoenix_function.hpp&gt; #include &lt;boost/spirit/include/qi.hpp&gt; using std::string; using boost::spirit::qi::grammar; using boost::spirit::qi::rule; using boost::spirit::qi::space_type; using boost::spirit::qi::skip_flag; using boost::spirit::unused_type; namespace qi = boost::spirit::qi; namespace phx = boost::phoenix; struct make_line_impl { int* _context; make_line_impl(int* context) { _context = context; } template &lt;typename Sig&gt; struct result; template &lt;typename This, typename Arg&gt; struct result&lt;This(Arg const &amp;)&gt; { typedef int* type; }; template &lt;typename Arg&gt; int* operator()(Arg const &amp; content) { return new int(5); } }; template&lt;typename Iterator&gt; struct MyGrammar : grammar&lt;Iterator, unused_type, space_type&gt; { rule&lt;Iterator, unused_type, space_type&gt; start; rule&lt;Iterator, int*(), space_type&gt; label; rule&lt;Iterator, string*(), qi::locals&lt;int*&gt;, space_type&gt; line; MyGrammar() : MyGrammar::base_type(start) { make_line_impl mlei(new int(5)); phx::function&lt;make_line_impl&gt; make_line(mlei); start = *(line); line = label[qi::_a = make_line(qi::_1)]; } }; int main(int argc, char **argv) { string contents; qi::phrase_parse(contents.begin(), contents.end(), MyGrammar&lt;string::iterator&gt;(), space_type(), skip_flag::postskip); return 0; } </code></pre>
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