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    <p>Keys are not ordered in NSDictionaries, so you have to sort the keys first before using them in your table view. So, instead of using [self.datasource allKeys] to get your section titles, first create a sorted array: sorted = [[self.datasource allKeys] sortedArrayUsingSelector:@selector(caseInsensitiveCompare:)], and then use that array to get the titles: title = [sorted objectAtIndex:section]. </p> <p>After Edit to answer a further question:</p> <p>To use the sorted array to get the values you want into your table, I think this should be close. You would have to add a property, NSArray *sorted, to your .h file, and then this in your .m (this is assuming the structure of your json is as you posted above):</p> <pre><code> NSDictionary *results = [jsonString JSONValue]; NSDictionary *all = [results objectForKey:@"categories"]; self.datasource = all; self.sorted = [[self.datasource allKeys] sortedArrayUsingSelector:@selector(caseInsensitiveCompare:)]; - (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView { return [self.sorted count]; } - (NSString *)tableView:(UITableView *)tableView titleForHeaderInSection:(NSInteger)section { NSString *title = [self.sorted objectAtIndex:section]; return title; } - (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section { return [[self.datasource valueForKey:[self.sorted objectAtIndex:section]]count]; } - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *cellIdentifier = @"Cell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:cellIdentifier]; if (cell == nil) { cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:cellIdentifier]; } NSArray *theArray = [self.datasource valueForKey:[self.sorted objectAtIndex:indexPath.section]]; NSString *text1 = [[theArray objectAtIndex:0] valueForKey:@"key1"]; NSString *text2 = [[theArray objectAtIndex:0] valueForKey:@"key2"]; cell.textLabel.text = [NSString stringWithFormat:@"%@\r%@",text1,text2]; cell.textLabel.numberOfLines=0; // this set the number of lines to unlimited return cell; } </code></pre> <p>You didn't say how you wanted to display two different values in one table row -- in this example, I concatenated them into one string with a return between the two.</p>
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    1. COthe section title values are not in alphabets order and they contains no number, so they cannot be compare... in fact they are listed in order within the JSON...
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    2. COIf they are strings you can sort them with compare. Are they not strings? It doesn't matter if they're sorted in the JSON, when you convert it to a dictionary it won't necessarily be in order any more.
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    3. COyes, they are string... but they are in Japanese characters, so I am not sure how to sort them to get the same order as in the JSON file...
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Guidance
A row detail

Detail views are divided into sections. All the information in the data section comes from columns in the selected row. The other sections display data from other, related rows.

Related data can be related in a to-one or a to-many fashion. Captions of data related in a to-many fashion link to a list view showing a filtered view of the table.

Try moving around until you find a non-empty to-many entry and click on the label to get to one. You can move back to the root by clicking on the database name in the header.

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