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POThe simplest (or at least the one functional) way to init JSON obejct from URL (Geocoding API)
 

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  1. POThe simplest (or at least the one functional) way to init JSON obejct from URL (Geocoding API)
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    <p>Im trying to geocode in my javascript code against Geocoding API. I get url defined <code>var url = "http://http://maps.googleapis.com/maps/api/geocode/json?address=New York, Manhattan&amp;sensor=false" </code> from which I need to retrive a JSON object. First approach I used was according to Wikipedia using XmlHttpRequest like this</p> <pre><code>var my_JSON_object = {}; var http_request = new XMLHttpRequest(); http_request.open("GET", url, true); http_request.onreadystatechange = function () { var done = 4, ok = 200; if (http_request.readyState == done &amp;&amp; http_request.status == ok) { my_JSON_object = JSON.parse(http_request.responseText); } }; </code></pre> <p>I run the code and get such output in debugger after open() function was triggered:</p> <pre><code>http_request: XMLHttpRequest onabort: null onerror: null onload: null onloadend: null onloadstart: null onprogress: null onreadystatechange: function () { readyState: 1 response: "" responseText: "" responseType: "" responseXML: null status: [Exception: DOMException] statusText: [Exception: DOMException] upload: XMLHttpRequestUpload withCredentials: false __proto__: XMLHttpRequest </code></pre> <p>which means that nothing really useful obviously happened. My second approach was due to json.org, Ive tried to make a get call with JSONRequest</p> <pre><code>var requestNumber = JSONRequest.get( url, function (requestNumber, value, exception) { if (value) { document.write(value); } else { document.write(exception); } } </code></pre> <p>Debugger told me that JSONRequest is not defined! Due to json.org its native JS object so whats the problem? Just to notice, i use properly gained API key from google in the script nearby.</p> <p>Explanation why my solution failed and any suggestion how to comply with this task would be much appreciated!</p>
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    1. COThis is probably just a typo, but you have "http://" twice at the beginning of your url.
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