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    <p>Depending on what you need, the easiest option may be to use tuples as dictionary keys instead of nested dictionaries:</p> <pre><code>kidshair['allkids', 'child3', 'hair'] mypath = ('allkids', 'child3', 'hair') kidshair[mypath] </code></pre> <p>The only issue with this is that you can't get a portion of the dictionary, so, for example, you can't (easily/efficiently) access everything to do with <code>'child3'</code>. This may or may not be an appropriate solution for you depending on your usage.</p> <p>An alternative with your current structure is to do something like this:</p> <pre><code>&gt;&gt;&gt; from functools import partial &gt;&gt;&gt; test = {"a": {"b": {"c": 1}}} &gt;&gt;&gt; def itemsetter(item): ... def f(name, value): ... item[name] = value ... return f ... &gt;&gt;&gt; mypath = partial(itemsetter(test["a"]["b"]), "c") &gt;&gt;&gt; mypath(2) &gt;&gt;&gt; test {'a': {'b': {'c': 2}}} </code></pre> <p>Here we make a function <code>itemsetter()</code>, which (in the vein of <a href="http://docs.python.org/library/operator.html#operator.itemgetter" rel="nofollow"><code>operator.itemgetter()</code></a>) gives us a function that that sets the relevant key in the given dictionary. We then use <a href="http://docs.python.org/library/functools.html#functools.partial" rel="nofollow"><code>functools.partial</code></a> to generate a version of this function with the key we want pre-filled. It's not quite <code>mypath = blue</code> either, but it's not bad.</p> <p>If you don't want to bother with making something consistent to the <code>operator</code> module, you could simply do:</p> <pre><code>def dictsetter(item, name): def f(value): item[name] = value return f mypath = dictsetter(test["a"]["b"], "c") mypath(2) </code></pre>
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    1. POStoring dictionary path in Python
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    1. USGareth Latty
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    1. COBrilliantly described, allowed me to more than solve my problem. Sincere thanks.
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      1. USDom Vinyard
 

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