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POHow to properly load a Database row into a class in php
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2012-04-28T01:03:35.580
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2012-05-04T13:37:55.510
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I am using Kohana 3.2, not that it matters much, but I am writing an application where I am wrapping any and all returned database records in a specific class. I don't know that I understand the best way to load the database row into the class, because sometimes it is a ORM model and sometimes it might just be an row ID. So from a controller if I wanted a list of all the users it would look something like: Controller: <pre><code>$users = User::find_all(); </code></pre> User Class <pre><code>public static function find_all() { $users_model = ORM::factory('user')->find_all(); $users = array(); foreach ($users_model as $user_model) { $users[] = User::instance($user_model); } return $users; } </code></pre> That works great, but sometimes I need to load a user object with just an id, like after some action, again a example: Controller <pre><code>$user_id = $_POST['user_id']; $user = User::instance($user_id); </code></pre> So is the User class responsible for trying to identify if an ID or a ORM object was passed into it. It seems like that isn't right for good OOP practices, but I am really not sure what the best way to do it is. What I have been currently doing is in the construct: <pre><code>public function __construct($user, $load = 'model') { if ($load == 'model') { $this->user_model = $user; } if ($load == 'id') { $this->user_model = ORM::factory('user', $user); } } </code></pre> But that really just doesn't feel right. Any advice would be greatly appreciated.
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<php><oop><kohana>
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How to properly load a Database row into a class in php
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1. COWhats the reason of this wrapping? Why dont use existing Model_User class for your needs?
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