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POSimple jQuery ajax example not finding elements in returned HTML
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2009-06-23T15:50:28.117
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2015-02-15T08:42:05.020
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<p>I'm trying to learn jQuery's ajax functions. I've got it working, but jQuery doesn't find elements in the returned HTML DOM. In the same folder as jquery, run this page:</p> <pre><code><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" lang="en" xml:lang="en"> <head> <title>runthis</title> <script type="text/javascript" language="javascript" src="jquery-1.3.2.min.js"></script> <script tyle="text/javascript"> $(document).ready(function(){ $('input').click(function(){ $.ajax({ type : "GET", url : 'ajaxtest-load.html', dataType : "html", success: function(data) { alert( data ); // shows whole dom alert( $(data).find('#wrapper').html() ); // returns null }, error : function() { alert("Sorry, The requested property could not be found."); } }); }); }); </script </head> <body> <input type="button" value="load" /> </body> </html> </code></pre> <p>Which loads this page "ajaxtest-load.html":</p> <pre><code><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" lang="en" xml:lang="en"> <head> <title>load this</title> </head> <body> <div id="wrapper"> test </div> </body> </html> </code></pre> <p>It gives two alerts. One showing the DOM was loaded, but the second shows NULL instead of the #wrapper. What am I doing wrong? </p> <p>EDIT: I'm loading "ajaxtest-load.html" which includes the whole header, including jquery again. Is that the issue?</p>
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<jquery><ajax><dom><parsing>
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Simple jQuery ajax example not finding elements in returned HTML
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1. COPerhaps clean up the top code and post what the html looks like on 'ajaxtest-load.html'
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2. COThe second html block is ajaxtest-load.html. Edited the description. Sorry about that.
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