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    <p>You only need to check the <em>edges</em> of the bounding box. Some pseudo code could look like.</p> <pre><code>if Rect1[RIGHT] &lt; Rect2[LEFT] or Rect1[LEFT] &gt; Rect2[RIGHT] or Rect1[TOP] &lt; Rect2[BOTTOM] or Rect1[BOTTOM] &gt; Rect2[TOP] then return false else return true </code></pre> <p>What this is trying to say is that if there are any possible gaps along the X or Y coordinate system separating the boxes then a collision is not possible. This is a <em>very</em> simple version of the <a href="http://www.codezealot.org/archives/55" rel="noreferrer">SAT (Separating Axis Theorem)</a> </p> <p>A little image of what this looks like visually, the same idea is applied here also.</p> <p><img src="https://i.stack.imgur.com/eSdbx.png" alt="Visualisation of SAT"></p> <p>This should mean that something similar to the following should work. Please note I haven't testing it but could lead you in the right direction.</p> <pre><code>public boolean collidesWith(ICollider otherObj) { GameObject gObj = (GameObject) otherObj; //this collider int r1 = (int) (getX() + getWidth()/2); int l1 = (int) (getX() - getWidth()/2); int t1 = (int) (getY() + getHeight()/2); int b1 = (int) (getY() - getHeight()/2); //the other collider int r2 = (int) (gObj.getX() + gObj.getWidth()/2); int l2 = (int) (gObj.getX() - gObj.getWidth()/2); int t2 = (int) (gObj.getY() + gObj.getHeight()/2); int b2 = (int) (gObj.getY() - gObj.getHeight()/2); if (r1 &lt; l2 || l1 &gt; r2 || t1 &lt; b2 || b1 &gt; t2) return false; else return true; /* Or could be shortened down to return !(r1 &lt; l2 || l1 &gt; r2 || t1 &lt; b2 || b1 &gt; t2) */ } </code></pre> <p>quite a reduction in code wont you say ;)</p>
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    1. COI Have actually tried this before. The problem is that this operation always returns true for some object When its compared to every object in the gameWorld even when the object(ball) is in the middle of the screen touching nothing. If you picture two squares directly next to each other but not touching then r1 will be less than l2 which is incorrect so in my original example that I posted I tried comparing all of the corresponding sides but that didn't work either.
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    2. COApologies i believed I miss typed it. The returns should be the opposite :/. I have edited the answer.
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    3. COHave you managed to get this working yet?
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